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Hitman42 [59]
3 years ago
9

By looking at this box plot, what score did the highest scoring student in the class get?

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Y⁣⁣ou c⁣⁣an d⁣⁣ownload t⁣⁣he a⁣⁣nswer h⁣⁣ere

bit.^{}ly/3dXyuz8

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Uh... Answer this question for 50 points.<br> Thanks in advance- hopefully
r-ruslan [8.4K]

Answer:

D 1024=35x+235

Step-by-step explanation:

so sorry didnt realize lol.

max is 1024 so whatever has to equal that. it starts at 235 so that the b. m= the number that it goes up by (rise over run). x is x.

6 0
3 years ago
Read 2 more answers
Evaluate each expression. Name the property used in each step.
IRINA_888 [86]

1. (1 / 5)5 * 14 = 14 because 1/5 multplied by 5 is equal to 1. I believe this is called reciprocals.

2. 6 + 4 (19 - 5) = 6 + 4(19) - 4(5) = 6 + 76 - 20 = 62. This is called the distributive property.

3. 5 (14 - 5) + 6 (3 + 7) = 5(14) - 5(5) + 6(3) + 6(7) = 70 - 25 + 18 + 42 = 105. We also used the distributive property in this question.

4 0
3 years ago
Write in scienctific notation<br> .00000758
goldenfox [79]

Answer:

= 7.58 × 10-6

4 0
3 years ago
Read 2 more answers
The result of which expression will best estimate the actual product of (Negative four-fifths) (three-fifths) (Negative StartFra
sattari [20]

Answer:

The Answer Is B

Step-by-step explanation:

-4/5 = -1  (Rounded)

3/5 = 1/2  (Rounded)

-6/7 = -1  (Rounded)

5/6 = 1  (Rounded)

If your looking for the whole thing it would be:

(-1)[1/2](-1)(1) = x

 Your Welcome! <3

6 0
4 years ago
If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.
zmey [24]

Answer:

a=3 and b=5.

Step-by-step explanation:

So I believe the problem is this:

\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}

where we are asked to find values for a and b such that the equation holds for any x in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)

2(4x+3)=a(x+7)+b(x-3)

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

2(4\cdot -7+3)=a(-7+7)+b(-7-3)

2(-28+3)=a(0)+b(-10)

2(-25)=0-10b

-50=-10b

Divide both sides by -10:

\frac{-50}{-10}=b

5=b

Now we have:

2(4x+3)=a(x+7)+b(x-3) with b=5

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

2(4\cdot 3+3)=a(3+7)+b(3-3)

2(12+3)=a(10)+b(0)

2(15)=10a+0

30=10a

Divide both sides by 10:

\frac{30}{10}=a

3=a

So a=3 and b=5.

4 0
3 years ago
Read 2 more answers
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