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Dmitry_Shevchenko [17]
3 years ago
5

Please can help me ?

Mathematics
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:

??????????????

Step-by-step explanation:

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Mr. Suh puts $1,500.00 into savings bonds that pay a simple interest rate of 2.5%. How much money will the bonds be worth at the
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i have no idea

Step-by-step explanation:

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3 years ago
A person invests $1,150 in an account that earns 5% annual interest compounded continuously. Find when the value of the investme
AfilCa [17]

Answer:

11.1 years

Step-by-step explanation:

The formula for interest compounding continuously is:

A(t)=Pe^{rt}

Where A(t) is the amount after the compounding, P is the initial deposit, r is the interest rate in decimal form, and t is the time in years.  Filling in what we have looks like this:

2000=1150e^{{.05t}

We will simplify this first a bit by dividing 2000 by 1150 to get

1.739130435=e^{.05t}

To get that t out the exponential position it is currently in we have to take the natural log of both sides.  Since a natural log has a base of e, taking the natual log of e cancels both of them out.  They "undo" each other, for lack of a better way to explain it.  That leaves us with

ln(1.739130435)=.05t

Taking the natural log of that decimal on our calculator gives us

.5533852383=.05t

Now divide both sides by .05 to get t = 11.06770477 which rounds to 11.1 years.

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3 years ago
Native people in the Amazon Rainforest use a toxin to help them catch fish. The toxin interferes with the gas exchange in the fi
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A

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3 years ago
1. What is the place value of the 1 in 1,234,567,890? ​
FrozenT [24]

Answer:

The place value of 1 in 1,234,567,890 is <u>1</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>.</u>

4 0
2 years ago
Read 2 more answers
How many zeros in the standard form of 10/3
Slav-nsk [51]

If you meant, "how many zeros are there in the standard form of 'ten divided by 3,' the answer would be, "none."


10/3 = 3.3333333333333.... This is a repeating decimal.


7 0
4 years ago
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