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2 years ago

Can I please get some help with this?

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

3 0

Answer: if this is any help look up slander on the internet and type in your math work book and but in your unit and your answer should be there.

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Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: h (h(x)) and. g (h (x))

ki77a [65]

H(h(x)) means to use the entire function h(x) as the x value in the function h(x)..

h(h(x)) = (x²+1)² + 1
= (x²+1)(x²+1) + 1
= (x^4 + x² + x² + 1) + 1
= x^4 + 2x² + 2

g(h(x)) means to use the entire function h(x) as the x value in the function g(x)..

g(h(x)) = 3(x² + 1)
= 3x² + 3
g(h(x))

7 0

2 years ago

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct. Suppose that one of the st

Alex

Answer:

0.0111% probability that he answers at least 10 questions correctly

Step-by-step explanation:

For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct.

This means that $n = 15, p = \frac{1}{5} = 0.2$

What is the probability that he answers at least 10 questions correctly?

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.2)^{10}.(0.8)^{5} = 0.0001$

$P(X = 11) = C_{15,11}.(0.2)^{11}.(0.8)^{4} = 0.000011$

$P(X = 12) = C_{15,12}.(0.2)^{12}.(0.8)^{3} \cong 0$

$P(X = 13) = C_{15,13}.(0.2)^{13}.(0.8)^{2} \cong 0$

$P(X = 14) = C_{15,14}.(0.2)^{14}.(0.8)^{1} \cong 0$

$P(X = 15) = C_{15,15}.(0.2)^{15}.(0.8)^{0} \cong 0$

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.0001 + 0.000011 = 0.000111$

0.0111% probability that he answers at least 10 questions correctly

3 0

2 years ago

PLEASE HELP!! GRADE 7 MATHEMATICS!!!

Rzqust [24]

The area of 3x5 face is used 4 times rather then twice
S=94in ^2

5 0

3 years ago

2. Lorena is trying to choose between two different savings accounts at H-Town Bank. She will deposit $3,500 dollars and will le

Ivahew [28]

Answer:

First of all, this question is not complete. So, we will be hypothetically create two accounts and try to choose the one with the greater profit.

Choice 1 = X = Final Amount after 12 years = $5600

Choice 2 = Y = Final Amount after 12 years = $6285.50

Hence, Lorena should choose choice 2, as it gives more profit over than choice 1.

Step-by-step explanation:

First of all, this question is not complete. So, we will be hypothetically create two accounts and try to choose the one with the greater profit.

Initial Deposit Amount = $3500

Time period = 12 years

Let's Suppose Lorena has two X and Y choices of accounts at H-town Bank.

X = simple interest of 5% over the initial amount for 12 years.

Y = Compound interest 5% over the initial amount for 12 years.

Solution:

Let's calculate the profit for choice 1 = X

Simple interest = 5%

Initial amount = $3500

Time period = 12 years

Formula = A = P (1 + rt)

where, A = Final amount after 12 years

t = time period in years = 12

P = initial amount to be deposited = $3500

r = annual interest rate = 5%

Plug in the values to get the total amount.

A = 3500(1+0.05x12)

A = $5600 = final amount Lorena will get after 12 years.

Let's calculate the profit for choice 2 = Y

Compound interest = 5%

Initial amount = $3500

Time period = 12 years

Formula = A = P $(\frac{r}{n} + 1)^{nt}$

where,

A = Final amount after 12 years

t = time period in years = 12

P = initial amount to be deposited = $3500

r = annual interest rate = 5%

n = number of times interest rate is applied or compounded. = 12

Plug in the values to get the total amount.

A = P $(\frac{r}{n} + 1)^{nt}$

A = $6285.50

Hence, Lorena should choose choice 2, as it gives more profit over than choice 1.

4 0

2 years ago

Can someone help me with this

aleksandrvk [35]

Answer:

the answer to the second question is h^9

Step-by-step explanation:

you are subtracting 14-5=9

5 0

2 years ago