B. Homogeneous
Look we have two types of mixture
1. Homogeneous: include solution
2. Heterogeneous: that include colloid & suspension
<span>No of moles of Fe = Mass / Relative molar mass of Fe. So no of moles = 89.4/ 55.845 = 1.60. The. Chemical reaction is represented as follows. 4 Fe + 3 O2 which gives 2Fe2 O3 . This means that 4 atoms of Iron reacts with 3 atoms of Oxygen to produce Iron oxide. Hence 1.60*4 moles of Fe will need to react 1.6 * 3 moles of Oxygen to produce 2 moles of Iron oxide. Hence 4.8 moles of Oxygen will be required.</span>
65 are required to produce 37.15 g CO2
The balanced chemical reaction is written as :
Na2CO3<span> + 2HCl === 2NaCl + H2O + CO2
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We are given the amount of NaCl to be produced from the reaction. This will be the starting point for the calculations. We do as follows:
120 g NaCl ( 1 mol / 58.44 g) ( 1 mol Na2CO3 / 2 mol NaCl)( 105.99 g / 1 mol ) = 1108.82 g Na2CO3 needed