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Shkiper50 [21]
3 years ago
6

Why is thinking of a homework plan is not a form of work?

Chemistry
1 answer:
fredd [130]3 years ago
8 0
This don’t make sense ??
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he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c
Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is 61.29M^{-1}s^{-1}

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{244^oC} = equilibrium constant at 244°C = 6.7M^{-1}s^{-1}

K_{324^oC} = equilibrium constant at 324°C = ?

E_a = Activation energy = 71.0 kJ/mol = 71000 J/mol   (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 244^oC=[273+244]K=517K

T_2 = final temperature = 324^oC=[273+324]K=597K

Putting values in above equation, we get:

\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}

Hence, the rate constant at 324°C is 61.29M^{-1}s^{-1}

8 0
3 years ago
Why is cl2 a subcript​
vazorg [7]

Answer:

In Cl_2, the 2 is a subscript because it indicates there are 2 of the same elements. The Lewis structure would display it as Cl-Cl.

On the other hand, a superscript would indicate a specific charge.

All subscripts show the amount of the specific element there is.

An example would be O_2\\ or N_2, they both show that there are 2 of the same elements.

If the subscript is outside a parenthesis such as Ca_3(PO_4)_2 it indicates there are 2 PO_4 molecules.

5 0
3 years ago
Write the balance nuclear equation showing the decay of zinc-69 to gallium-69
Taya2010 [7]

Answer:

It is a beta decay equation unknown

Explanation:

none

5 0
3 years ago
Fill in the blanks using terms from this unit.
kolbaska11 [484]

Answer:

See the answer below

Explanation:

Even though plants are rooted in the ground, they still move, exert <u>force,</u> and do<u> work</u>.

Plant cells have very strong cell walls that allow <u>pressure</u> to build up inside of the cell as water is absorbed. This pressure is called <u>turgor</u>.

When turgor pressure is high enough in a cell, the cell walls become <u>firm</u> and as a result, the cell becomes rigid and the plant is able to stand <u>tall</u> and<u> straight</u>.

When a plant does not get enough water, the turgor pressure inside of the cells <u>decreases.</u> A decrease in <u>pressure</u> pushing against the cell wall causes the cells to lose their <u>shape</u> and <u>shrink</u>. This causes the plant to begin to droop or <u>wilt</u>.

When the wilted plant gets enough water, the cells will become rigid again, and the plant will stand firm and straight once again.

5 0
3 years ago
Read 2 more answers
Use the mass and volume data to calculate the density of an unknown metal to the nearest hundredth.
11Alexandr11 [23.1K]

Answer:

8.90

Explanation:

Density = mass ÷ volume

D = 222.50 g ÷ 25.00

= 8.9

The density of the unknown metal is 8.90.

Hope that helps.

8 0
3 years ago
Read 2 more answers
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