Will mark branliest!! and 50 points for right answer!

Which has the reverse chemical reaction as

Mazyrski [523]

Answer:

please further explain your question

4 0

3 years ago

The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.

Pachacha [2.7K]

Answer : The molecular formula of the compound will be, $C_{3}H_{6}O_3$

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

As we are given that the empirical formula of a compound is $CH_2O$ and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of $CH_2O$ = 1(12) + 2(1) + 1(16) = 30 g/eq

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

$n=\frac{90.09}{30}=3$

Molecular formula = $(CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3$

Thus, the molecular formula of the compound will be, $C_{3}H_{6}O_3$

7 0

3 years ago

If the rate of a reaction increases by a factor of 64 when the concentration of reactant increases by a factor of 4, what is the

igomit [66]

The reaction is of order three with respect to the reactant.

<h3>Explanation</h3>

The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if concentrations of any other reactants stay constant in the whole process.

In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)

In this question,

[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.

In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.

It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:

$\ln{4^n} = \ln{64}\\n\; \ln{4} = \ln{64}\\n = \frac{\ln{64}}{\ln{4}} = 3$ .

Evaluating $\ln(64) / \ln(4)$ on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.

n = 3. Therefore, the reaction is of order three with respect to this reactant.

3 0

3 years ago

Compare the trends for atomic size and first ionization energy.

bazaltina [42]

Explanation:

On a periodic table, the atomic size is depicted by the radius of the atom.

Across a period, the atomic radius reduces progressively from left to right.

Down the group from top to bottom, atomic radii increases progressively.

For the ionization energy, from left to right, across the period, it increases progressively and down a group it reduces.

These two trends are related in that as the atomic radius decreases across the period there is an increasing nuclear charge which is not compensated for by the the successive shells of electrons being added. This also similar down the group.

6 0

2 years ago

A group of electrons is treated as a point charge of -1.12 x 10-18 C. How many electrons make up this point charge? Remember tha

Pepsi [2]

Answer:

7

Explanation:

Given that the total charge is given by;

C =nq

Where;

n = number of charges

q = quantity of charge

Where the total amount of charge is -1.12 x 10-18 C and the magnitude of each charge is -1.602 x 10-19 C

Then the number of electrons is obtained from;

n = -1.12 x 10-18 C/ -1.602 x 10-19 C

n = 7

4 0

3 years ago