Answer:
ΔH°rxn = 39013.33 J/mol = 39.013 kJ/mol.
Explanation:
- We can calculate the amount of heat (Q) released from the solution using the relation:
<em>Q = m.c.ΔT,</em>
Where, Q is the amount of heat released from the solution (Q = ??? J).
m is the mass of the solution (m of the solution = density of the solution x volume of the solution = (1.0 g/mL)(200 mL) = 200 g.
c is the specific heat capacity of the solution (c = 4.18 J/g∙°C).
ΔT is the difference in the T (ΔT = final temperature - initial temperature = 23.20 °C - 21.80 °C = 1.4 °C).
∴ Q = m.c.ΔT = (200 g)(4.18 J/g∙°C)(1.4 °C) = 1170.4 J.
∵ ΔH°rxn = Qrxn/(no. of moles of AgNO₃).
Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.
M = (no. of moles of AgNO₃)/(Volume of the solution (L)).
∴ no. of moles of AgNO₃ = (M)(Volume of the solution (L)) = (0.3 M)(0.1 L) = 0.03 mol.
∴ ΔH°rxn = Qrxn/(no. of moles of AgNO₃) = (1170.4 J)/(0.03 mol) = 39013.33 J/mol = 39.013 kJ/mol.