Recycling!! And also planting more trees.
Hope this helps!
Answer:
A) is true
Explanation:
For the reaction:
O₂(g) + 2F₂(g) ⇄ 2OF₂(g); Kp = 2,3x10⁻¹⁵
kp is defined as:
Kp = 2,3x10⁻¹⁵ = [OF₂]²/[O₂] [F₂]²
A) If the reaction mixture initially contains only OF₂(g), then at equilibrium, the reaction mixture will consist of essentially only O₂(g) and F₂(g). <em>TRUE. </em>As the kp is 2,3x10⁻¹⁵ means per 1 of [O₂] [F₂]² you will have just 2,3x10⁻¹⁵ of [OF₂]²
B) For this equilibrium, Kc = Kp. <em>FALSE. </em>That is true just when moles of reactants are the same than moles of products. Here there are 3 moles of reactants vs 2 moles of products.
C) If the reaction mixture initially contains only OF₂(g), then the total pressure at equilibrium will be less than the total initial pressure. <em>FALSE. </em>Because per 2 moles of OF₂(g) you will produce 3 moles of gas increasing pressure.
D) If the reaction mixture initially contains only O₂(g) and F₂(g), then at equilibrium, the reaction mixture will consist of essentially only OF₂(g). <em>FALSE. </em>For the same reason of A), the mixture will contains essentially only O₂(g) and F₂(g)
E) If the reaction mixture initially contains only O₂(g) and F₂(g), then the total pressure at equilibrium will be greater than the total initial pressure. <em>FALSE. </em>If mixture initially contains only O₂(g) and F₂(g), 3 moles will of gas will react to produce 2 moles of gas doing pressure decreases.
I hope it helps!
Answer: Use c1(v1) = c2(v2) to solve<span> that </span>problem. 87%(200) = (35.5<span>%)v2 v2 ≈ 490.5. I hope this helps! Source(s)</span>
The energy of an electron can be change only by set amounts.
The electrons in an energy level of an atom can only move to a higher or lower energy level only if it absorbs or emits a certain amount of energy. If the electron does not have enough energy to move to the next energy level then it will never move.