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Likurg_2 [28]
3 years ago
6

Someone write down the answers plllsss!!! help

Mathematics
2 answers:
damaskus [11]3 years ago
8 0

Step-by-step explanation:

4= x>6

5(a)=x<5

5(b)=

( - 2. \infty )

If you need any explanation in it or anything on math you can communicate with me on Whats on this number +201557831028 or in email or face or anything

SOVA2 [1]3 years ago
5 0

Answer:

I may help u with this ques but I am somewhere out, so Sorry

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Find the coordinates of the center and the measure of the radius for a circle whose equation is (x - 3)^2 + (y - 7)^2 = 2.
zloy xaker [14]

Answer:

A

Step-by-step explanation:

Equation for a circle of radius r, centered at (h,k):

(x-h)² + (y-k)² = r²

3 0
3 years ago
Question 29: In a club of 35 boys and 28 girls, 80% of the boys and 25% of the girls have been members for more than 2 years. If
klasskru [66]

Answer:

55%

Step-by-step explanation:

What we must do is get the total number of people, that is, boys and girls who have been a member for more than 2 years, that is:

children: 0.8 * 35 = 28

girls = 0.25 * 28 = 7

Now, passing knowing the%, would be dividing the sum of the above by the sum of the total club members:

(28 +7) / (35 + 28) = 0.55

Since it is a number below 1, it cannot be a mixed number.

3 0
4 years ago
Read 2 more answers
4/5x = 3<br> please solve for x
san4es73 [151]

Answer:

x=15/4 or x=3.75

Step-by-step explanation:

4/5*x=3

4/5=0.8

0.8*3.75=3

3 0
3 years ago
Hi what is the answer for this
svp [43]

<u><em /></u>

a   = a   + d(n-1)

 n      1

this is the formula for the arithmetic sequence.

the first sequence is arithmetic

an=1+7(n-1)

the second sequence is also arithmetic

an=12+4(n-1)

5 0
4 years ago
Read 2 more answers
9. The sum of two consecutive integers is 41 less than<br> four times the larger. Find the numbers.
Maksim231197 [3]

Answer:

19 and 20

Step-by-step explanation:

Let x be the larger number

x - 1 + x = 4x - 41

We can combine like terms and isolate x:

2x - 1 = 4x - 41

2x = 40

x = 20

20 - 1 = 19

5 0
3 years ago
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