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2 years ago

Round 471.42857 to the nearest cent

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

6 0

Answer:

471

Step-by-step explanation:

do to the number in the tenths place not being higher than 5 all number past the decimal become zero and the whole number stay the same

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Y=300-5x in standard form

Akimi4 [234]

y = 300 - 5x

Standard form:
ax + by = c

y = 300 - 5x
5x + y = 300

Then to find the y-intercept, insert a 0 into the 'x'.
5(0) + y = 300
y = 300
The y-intercept is 300.

To find the x-intercept, insert a 0 into the 'y'.
5x + (0) = 300
5x = 300
x = 60

The x-intercept is 60.

8 0

2 years ago

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In Walmart parking, there are 175 vehicles parked joe figures out that 64% of the vehicles are white. How many vehicles are NOT

aksik [14]

Answer:

63 vehicles are not white

Step-by-step explanation:

Well you know that there are 175 total vehicles, and that 64% of those vehicles are white. Therefore the remaining percentage of vehicles must not be white.

100%-64%=36%

This means that 36% of the vehicles aren't white.

Now you must find what 36% of 175 is. The word "of" always signals for multiplication, which is exactly what you need to do here. First start by converting the percentage into decimal form:

36%=0.36

Now you can multiply

175 x 0.36 = 63

63 Vehicles are not white

5 0

2 years ago

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

Solve the system of equations

Phoenix [80]

The correct answer is letter B, (6,-1).

When you substitute this ordered pair on the equations, you would found out is the correct one.

6 0

2 years ago

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Please Help What is the equation of the line?

Rama09 [41]

The line doesn’t appear to be moving, so I believe it’s just y=4.

4 0

2 years ago

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