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NNADVOKAT [17]
3 years ago
14

"The sum of renting bowling shoes and $3 per game"

Mathematics
1 answer:
Serga [27]3 years ago
4 0
Yes yes yes yes yes yes yes yes
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Make an assumption . ''to assume''
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3 years ago
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Finding domain f(x)=3x+1/x-5
arlik [135]
The function is undefinded if the denominator, x-5, equals 0.
So x-5 \neq 0 \\ 
x \neq 5.
The domain is x \neq 5.
In interval notation, this is (-infinity, 5) u (5, infinity).
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3 years ago
Questions are in file/pictures! <br><br> (as you can see all my questions are from math lol)
77julia77 [94]

Answer:

the first one would be 12 square feet

the second one would be 2961$

and the third one would be 125%

Step-by-step explanation:

i took the test

5 0
3 years ago
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2
Oksanka [162]

If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width

Solution:

Let the length of rectangle=x

Width of rectangle=x/10

Perimeter is 2(Length+Width)

= 2(x+x/10)

Area of Rectangle= Length* Width=x*x/10

As, Perimeter=2(Area)

So,2(x+x/10)=2(x*x/10)

Multiplying the equation with 10, we get,

2(10x+x)=2x²

Adding Like terms, 10x+x=11x

2(11x)=2x^2

22x=2x²

2x²-22x=0

2x(x-11)=0

By Zero Product property, either x=0

or, x-11=0

or, x=11

So, Width=x/10=11/10=1.1

Checking:

So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2

Area=Length*Width=11*1.1=12.1

Hence, Perimeter= 2 Area

As,24.2=2*12.1=24.2

So, Perimeter=2 Area

So, Answer:Length of Rectangle=11 units

Width of Rectangle=1.1 units

7 0
3 years ago
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If x+1 and x-1 are the factors of the polynomial ax^3 + x^2 - 2x +b,find the values of a and b
Nadusha1986 [10]

The polynomial remainder theorem says that dividing a polynomial p(x) by x-c leaves a remainder of p(c)=0 if x-c is a factor of p(x). In this case, check c=-1 and c=1.

a(-1)^3+(-1)^2-2(-1)+b=-a+b+3=0

a(1)^3+(1)^2-2(1)+b=a+b-1=0

From the first equation,

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3 0
3 years ago
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