Answer:
x-intercept:8
y-intercept:16
Step-by-step explanation:
This is the equation of a straight line. When the line crosses the x-axis that is the x- intercept, the corresponding y-coordinate will be zero. Substituting y = 0 into the equation and solving for x gives the x-intercept.
8x-(4×0)=-64
-8x=-64
x=8 <= the x-intercept.
Similarly, when the line crosses the y-axis the corresponding x- coordinate will be zero. Let x = 0 and solve for y.
(8×0)-4y=-64
-4y=-64
y=16 <= the y-intercept
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Answer:
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Step-by-step explanation:
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Answer:
C, 5/2
Step-by-step explanation:
3 I2x -1I + 4 = 16
Isolate absolute value:
3 I2x -1I + 4 - 4 = 16 - 4
3 I2x -1I= 12
(3 I2x -1I) / 3 = 12 / 3
I2x -1I= 4
Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x
2x -1 = 4
2x -1 + 1 = 4 +1
2x = 5
2x / 2 = 5 / 2
x = 5/2 or C
