Answer:
1.7 moles of ammonia, NH₃.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4NH₃ + 5O₂ —> 4NO + 6H₂O
From the balanced equation above,
4 moles of NH₃ reacted to produce 4 moles of NO.
Finally, we shall determine the number of mole of ammonia, NH₃, needed to produce 1.7 moles of nitrogen monoxide, NO. This can be obtained as follow:
From the balanced equation above,
4 moles of NH₃ reacted to produce 4 moles of NO.
Therefore, 1.7 moles of NH₃ will also react to produce 1.7 moles of NO.
Thus, 1.7 moles of ammonia, NH₃, is required.
