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3 years ago

Which profession is likely to use a radiation shield?

Chemistry

2 answers:

Sidana [21]3 years ago

5 0

Answer:

astronomer

Explanation:

just took the test :)

pantera1 [17]3 years ago

3 0

Which profession is likely to use a radiation shield?
A.)dentist
B.)astronomer
C.)mathematician
D.)geologist

The answer is B: Astronomer

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Your mommy buys you a helium balloon at the circus. It has a volume of 2.95 liters. What is the mass

GrogVix [38]

Answer:

if my calculation are correct, it's 295 grams

Explanation:

because liters converted to grams is .1=100 so if you take 2.95 times 100, it equals 295

4 0

2 years ago

Force = 2.32 N Acceleration = 0.19 m/s2 Mass= ?

Mkey [24]

mass = 12.2 kg

Explanation:

To find the mass we use the following formula (Newton's Second Law of Motion):

force = mass × acceleration

mass = force / acceleration

mass = 2.32 N / 0.19 m/s²

mass = 12.2 kg

Learn more about:

Newton's Second Law of Motion

brainly.com/question/834262

#learnwithBrainly

3 0

2 years ago

True or false: All heterotrophs are omnivores.

RideAnS [48]

Answer:

False. They can be both omnivores and carnivores.

6 0

3 years ago

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

2 years ago

The elements Lithium (Li), Boron (B), and Oxygen (O) are all in the same _________ on the periodic table.

AnnyKZ [126]

Answer:

Period

Explanation:

If we ubicate te period one on the alkaline metals, we can see the lithium, so we go to the borans on te group AIII an we see Boron, move to the rigth on the same sense tou the group AVI we see the Oxygen, we can know that also for the electronic configuration Li:1s²2s¹ B:1s²2s²3p

7 0

2 years ago