<u>Answer:</u> The number of
ions dissociated are
<u>Explanation:</u>
We are given:
pH = 2.07
Calculating the value of pOH by using equation, we get:

To calculate hydroxide ion concentration, we use the equation to calculate pOH of the solution, which is:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
pOH = 11.93
Putting values in above equation, we get:
![11.93=-\log[OH^-]](https://tex.z-dn.net/?f=11.93%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=10^{-11.93}=1.17\times 10^{-12}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-11.93%7D%3D1.17%5Ctimes%2010%5E%7B-12%7DM)
To calculate the number of moles for given molarity, we use the equation:

Molarity of solution = 
Volume of solution = 1243 mL = 1.243 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:

According to mole concept:
1 mole of a compound contains
number of particles
So,
number of
will contain =
number of ions
Hence, the number of
ions dissociated are
To solve this problem, we assume ideal gas so that we can
use the formula:
PV = nRT
since the volume of the flask is constant and R is
universal gas constant, so we can say:
n1 T1 / P1 = n2 T2 / P2
1.9 mol * (21 + 273 K) / 697 mm Hg = n2 * (26 + 273 K) /
841 mm Hg
<span>n2 = 2.25 moles</span>
Answer:
hmmmmm very good question . igneous, or magmatic, in which minerals crystallize from a melt
sedimentary, in which minerals are the result of sedimentation
Heat and pressure
As hot water within Earth’s crust moves through
rocks, it can dissolve minerals. W
Explanation:
The process in which the concentration of the solution is lessened by the addition of water is said to be dilution and equation of dilution relates the initial concentration and volume of stock solution with the final concentration and volume of the solution.
Formula is given by:
(1)
where,
is the initial concentration
is the initial volume
is the final concentration
is the final volume
Now,
= 0.850 M
= 4.12 L
=?
= 10.00 L
Substitute the give values in formula (1),


= 
Thus, the final concentration of the
solution = 