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3 years ago

!!PLS HELP!! How many molecules are in 25.4g Tricarbon tetrahydride?

Chemistry

2 answers:

katovenus [111]3 years ago

4 0

<h2>Explanation←</h2>

This means 17 g of ammonia gas is = 1 mole of ammonia gas molecule. Sence, there are 8.856 x 1023 8.856 x 10 23 molecules in 25.4g of ammonia...

Anwser: 0.1651251733326733

My Caculations 78% might be right

<h2>How Its Created--></h2>

Ammonia is produced naturally from decomposition of organic matter, including plants, animals and animal wastes. Also, BACTERIA? Didn't know

Well now human being you know!

<h2><em>Defenition Of Ammonia</em></h2>

Well The Definiton of Ammonia is colourless, pungent gas composed of nitrogen and hydrogen. ... It is the simplest stable compound of these elements and serves as a starting material for the production of many commercially important nitrogen compounds.

Elena-2011 [213]3 years ago

3 0

That would be 3907.09658

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A 256 mL sample of HCl gas is in a flask where it exerts a force (pressure) of 67.5 mmHg. What is the pressure of the gas if it

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Answer:

The pressure in the new flask would be $128\; \rm mmHg$ if the $\rm HCl$ here acts like an ideal gas.

Explanation:

Assume that the $\rm HCl$ sample here acts like an ideal gas. By Boyle's Law, the pressure $P$ of the gas should be inversely proportional to its volume $V$ .

For example, let the initial volume and pressure of the sample be $V_1$ and $P_1$ . The new volume $V_2$ and pressure $P_2$ of this sample shall satisfy the equation: $P_1 \cdot V_1 =P_2 \cdot V_2$ .

In this question,

The initial volume of the gas is $V_1= 256\; \rm mL$ .
The initial pressure of the gas is $P_1 = 67.5\; \rm mmHg$ .
The new volume of the gas is $V_2 = 135\; \rm mL$ .

The goal is to find the new pressure of this gas, $P_2$ .

Assume that this sample is indeed an ideal gas. Then the equation $P_1 \cdot V_1 =P_2 \cdot V_2$ should still hold. Rearrange the equation to separate the unknown, $P_2$ . Note: make sure that the units for $V_1$ and $V_2$ are the same before evaluating. That way, the unit of

$\begin{aligned} & P_2\\ &= \frac{P_1 \cdot V_1}{V_2} \\ &= \frac{256\; \rm mL \times 67.5\; \rm mmHg}{135\; \rm mL} \\ & \approx 128\; \rm mmHg\end{aligned}$ .

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