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Svetlanka [38]
3 years ago
8

Please help meee! Chemistry!

Chemistry
2 answers:
Leya [2.2K]3 years ago
6 0

P=18000000/6 zeros. not sure how to do rest

mr Goodwill [35]3 years ago
6 0

Explanation:

a) n = \dfrac{PV}{RT} = \dfrac{(1.8×10^7\:\text{Pa})(3\:\text{L})}{(8310\:\text{L•Pa/mol•K})(300\:\text{K})}

\:\:\:\:\:\:\:= 21.7\:\text{mol}

b) P = \dfrac{nRT}{V}

\:\:\:\:\:\:\:\:\:= \dfrac{(50\:\text{mol})(8310\:\text{L•Pa/mol•K})(300\:K)}{(3\:L)}

\:\:\:\:\:\:\:\:\:=4.2×10^7\:\text{Pa}

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A gas cylinder initially contains 463 L of gas at a pressure of 159 atm. If the final volume of gas is 817 L, what is the final
Agata [3.3K]

Answer:

The final pressure is 90.1 atm.

Explanation:

Assuming constant temperature, we can solve this problem by using <em>Boyle's Law</em>, which states:

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Where in this case:

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We <u>input the given data</u>:

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And <u>solve for P₂</u>:

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6 0
3 years ago
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Answer:

1.7 × 10 ^42

Explanation:

Using Nernst equation

E°cell = RT/nF Inq

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Q=K

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Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

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2 Ag⁺ +2e⁻ → 2Ag

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E° cell = 0.80 + 0.45 = 1.25 V

E° cell = (0.0592 / n) log K  

substitute the value into the equations and solve for K

(1.25 × 2) / 0.0592  = log K

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8 0
3 years ago
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Answer:

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Explanation:

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--------------------- x ------------------------ = 119.85 grams Br or 120 grams Br (sig figs)

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7 0
3 years ago
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Answer:

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serg [7]

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It is the last one.

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