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3 years ago

7

A ramp has an angle of elevation of \displaystyle 20^{\circ}20 ∘ . It has a vertical height of 1.8 m. What is the length, L mete

rs, of the ramp? Round you answer to the nearest tenth of a meter.

1 answer:

juin [17]3 years ago

6 0

Answer:

5.3

Step-by-step explanation:

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Find the area of the triangle.<br> 10.<br> 15 cm<br> 16 cm

aev [14]

120
A= bh 1/2
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240/2
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In AABC, mZA=x, mZB = 2x +2, and

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Answer:

x = 29

Step-by-step explanation:

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If x²-5x +1 =0, what is the value of -<br><img src="https://tex.z-dn.net/?f=%28x%20%2B%20%20%5Cfrac%7B1%7D%7Bx%7D%20%29%20%20" i

ra1l [238]

<h3>Answer: 5</h3>

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Work Shown:

x^2 - 5x + 1 = 0

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---------------

An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.

In this case,

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3 years ago

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snow_lady [41]

Answer:

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

Average velocity = $\frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx$

= $\frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx$

now integrating

= $\frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )$

= $\frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}$

= $\frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))$

by using formulas

log a-log b = log(a/b)

on simplification , we get

= $\frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)$

= $log(\frac{7}{4} ) -2$

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3 years ago

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Furkat [3]

Answer:

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Step-by-step explanation:

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