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SVEN [57.7K]
3 years ago
7

4. Given: a + m = n, n= 4a; Prove: m = 3a

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Algebraic Manipulation</u>

It refers to the process of modifying algebraic expressions, often into a simpler form or more easily handled and dealt with.

It also helps us to prove some identities.

We are given the relations:

a + m = n

n = 4a

Substituting the last equation in the first, we have:

a + m = 4a

Subtracting a on both sides of the equation:

m = 4a - a

Simplifying:

m = 3a

Hence proved

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Answer:

The  condition  are

           The  Null hypothesis is  H_o  :  \mu = 5

           The  Alternative hypothesis is  H_a  :  \mu <  5

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Step-by-step explanation:

From the question we are told that

     The  population mean is  \mu =  5 \ year

      The sample size is  n =  20

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       The  standard deviation is \sigma  =  2.2  \ years

   The  Null hypothesis is  H_o  :  \mu = 5

   The  Alternative hypothesis is  H_a  :  \mu <  5

So i will be making use of  \alpha =  0.05 level of significance to test this claim

    The critical value of  \alpha from the normal distribution table is  Z_\alpha  =  1.645

 

Generally the test statistics is mathematically evaluated as

                 t =  \frac{\= x  - \mu}{ \frac{\sigma }{\sqrt{n} } }

substituting values

                 t =  \frac{ 4.6  - 5}{ \frac{2.2}{\sqrt{20} } }

                t =  -0.8131

Looking at the value of  t and Z_{\alpha } we see that  t <  Z_{\alpha } so we fail to reject the null hypothesis  

  This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

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