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3 years ago

4. Given: a + m = n, n= 4a; Prove: m = 3a

Mathematics

1 answer:

IrinaVladis [17]3 years ago

4 0

Answer:

Proof below

Step-by-step explanation:

Algebraic Manipulation

It refers to the process of modifying algebraic expressions, often into a simpler form or more easily handled and dealt with.

It also helps us to prove some identities.

We are given the relations:

a + m = n

n = 4a

Substituting the last equation in the first, we have:

a + m = 4a

Subtracting a on both sides of the equation:

m = 4a - a

Simplifying:

m = 3a

Hence proved

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4 years ago

julia is standing 2 feet away away from a lamppost. she casts a shadow of 5 feet and the light make a 20 degree angle relative t

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4 years ago

A quantitative data set has mean 23 and standard deviation 2. At least what percentage of the observations lie between 15 and 31

Elan Coil [88]

Answer:

Atleast 93.75% of data lies between 15 and 31.

Step-by-step explanation:

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We have to find he data lying between 15 and 31.

$15 = 23 - 4(2) = \mu - 4\sigma\\31 = 23 + 4(2) = \mu + 4\sigma$

Thus, we have to find the data lying within 4 standard deviation from the mean.

Chebyshev's Theorem:

According to this theorem atleast $1 - \dfrac{1}{k^2}$ percent of data lies within k standard deviation of mean.
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3 years ago

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Grace [21]

Answer:

h(d)= -2d^2 +4d +6

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Applying the vertex formula, a quadratic equation can be described by its vertex v(x,y) as follows:

$h=a*(d-x)^2 +y$

Since the vertex in this situation is at v (1,8):

$h=a*(d-1)^2 +8$

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Expanding the equation yields:

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4 years ago