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3 years ago

Karleigh walks 5/8 mile to school every day. How far does she walk to school in 5 days?

1 answer:

7 0

Hello!

To figure out how far Karleigh walks in 5 days, multiply the amount she walks in one day by 5.

$\frac{5}{8} *5$
$\frac{5}{8} * \frac{5}{1}$
$\frac{25}{8}$

Answer:
Karleigh walks $\frac{25}{8}$ or 3.125 miles to school in 5 days.

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a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu

Hunter-Best [27]

What you need to look for is $\frac { dr }{ dt }$ when r=8.

Now:

$Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }$

$\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr } } =\frac { 1 }{ 4\pi { r }^{ 2 } }$

$And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }$

$\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi }{ \pi } \cdot \frac { 1 }{ { r }^{ 2 } }$

$\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec$

3 0

3 years ago

Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ

tensa zangetsu [6.8K]

Answer: RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{18+x}{tan 75^{\circ}}$

Now, In triangle MRQ,

tan 60°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{x}{tan 60^{\circ}}$

On equating both values of RQ,

$\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=2.15470053838$

⇒ $18=2.15470053838x-x$

⇒ $x=15.5884572681$ ≈15.60

Thus RQ=8.99999999999≈8.99

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3 years ago

18. WILL MARK BRAINLIEST!!HELP!

vagabundo [1.1K]

Answer:

3x-20

Step-by-step explanation:

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3 years ago

Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 16 + 2x − x^2, [0, 5]

RSB [31]

Answer:

<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>

Step-by-step explanation:

To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.

at x = 0;

f(0) = 16 + 2(0) − 0²

f(0) = 16

at the other end point i.e at x = 5;

f(5) = 16 + 2(5) − 5²

f(5) = 16 + 10-25

f(5)= 26-25

f(5) = 1

The absolute minimum value is 1 and occurs at x = 5

The absolute maximum value is 16 and occurs at x = 0

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3 years ago

A scoop of ice cream is the shape of a whole perfect sphere sits in a right cone.

Andrei [34K]

Answer:

10 cm

Step-by-step explanation:

The volume of a sphere is given by the formula ...

V = 4/3πr³

The volume of a cone is given by the formula ...

V = 1/3πr²h

The ratio of the volume of the cone to that of the sphere is ...

Vcone/Vsphere = (1/3πr²h)/(4/3πr³) = h/(4r)

In order for the ratio to have a value of 1, we must have ...

h = 4r

The height of the cone must be 4×2.5 cm = 10 cm to fit all of the ice cream.

7 0

3 years ago

Read 2 more answers