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valina [46]
3 years ago
14

Unlike most chemical changes, most physical changes are easily reversed. When Adrian's teacher dissolves some sugar in a beaker

of water, the process involves a physical change. Adrian is asked to recover just the sugar in the solution. How can Adrian do this?
Chemistry
1 answer:
pochemuha3 years ago
8 0

Answer:

By heating the solution

Explanation:

Physical changes and chemical changes are the two types of changes that a substance undergoes. Physical change does not alter the substance's chemical composition, hence, can be easily reversed. There is also no new product formed. This is contrary to the occurrences of a chemical change, which cannot be reversed after a new product has been formed.

A physical change is what occurs when Adrian's teacher dissolves some sugar in a beaker of water to form a sugar solution. This change does not involve any new product formation, hence, can be reversed. The sugar can be derived back from the solution by HEATING THE SOLUTION. The water (solvent) will evaporate and the sugar (solute) will precipitate.

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How do colloids that exist in nature affect people
mel-nik [20]

The exposure of a person to colloids majorly present in industrial area may results in the accumulation in the body tissue which causes dark deposit in the skin. They are not safe and is dangerous for health which may cause turning of skin blue permanently and it is life long.

Whereas, the colloid of silver nitrate is used to treat skin burns and ulcers but its overuse may result in adverse effect.

4 0
3 years ago
What is the percent yield of CuS for the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? The actua
notka56 [123]

Answer:

(B) 42.1%

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Given: For Na_2S

Given mass = 15.5 g

Molar mass of Na_2S = 78.0452 g/mol

<u>Moles of Na_2S = 15.5 g / 78.0452 g/mol = 0.1986 moles</u>

Given: For CuSO_4

Given mass = 12.1 g

Molar mass of CuSO_4 = 159.609 g/mol

<u>Moles of CuSO_4 = 12.1 g / 159.609 g/mol = 0.0758 moles</u>

According to the given reaction:

Na_2S+CuSO_4\rightarrow Na_2SO_4+CuS

1 mole of Na_2S react with 1 mole of CuSO_4

0.1986 mole of Na_2S react with 0.1986 mole of CuSO_4

Available moles of CuSO_4 = 0.0758 moles

Limiting reagent is the one which is present in small amount. Thus, CuSO_4 is limiting reagent. (0.0758 < 0.1986)

The formation of the product is governed by the limiting reagent. So,

1 mole of CuSO_4 gives 1 mole of CuS

0.0758 mole of CuSO_4 gives 0.0758 mole of CuS

Molar mass of CuS = 95.611 g/mol

Mass of CuS = Moles × Molar mass = 0.0758 × 95.611 g = 7.2473 g

Theoretical yield = 7.2473 g

Given experimental yield = 3.05 g

% yield = (Experimental yield / Theoretical yield) × 100 = (3.05/7.2473) × 100 = 42.1 %

<u>Option B is correct.</u>

6 0
3 years ago
What part of a wind turbine provides motion to convert into electricity?
sineoko [7]
This is somewhat of a misleading question, because all of these elements are necessary to convert motion into electricity at some point, but the generator is the last in line.
3 0
3 years ago
Using molecular orbital theory, explain why the removal of one electron in O2 strengthens bonding, while the removal of one elec
Nuetrik [128]
First you have a knowledge of bond order which is
 B.O=(no. of electrons in bonding orbital - no. of electrons in non-bonding orbital)÷2  
Note:
bond strength is directly proportional to bond order.
For oxygen:
B.O=(6-2)/2= 2; after the removal of two electrons(removal occur from non-bonding orbital)
B.O=(6-0)/2= 3 (As B.O increased bond strength increased)
For Nitrogen:
B.O=(6-0)/2= 3; after the removal of two electrons(removal occur from bonding orbital)
B.O=(4-0)/2= 2 (As B.O decreased bond strength decreased)

6 0
3 years ago
If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the
Alchen [17]

In the first law of thermodynamics, it states when heat is converted into energy, where as the total energy in the room could transform into another but can never be created or destroyed. If you release 258J of energy in the room, 258J would also be removed from the food according to the isolating system.

Your answer would be 258J.

4 0
3 years ago
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