Answer: there were 12 chocolates in each box. (Originally, before any got eaten)
Step-by-step explanation: let x represent the total amount of chocolates in each box.
8x - 3(8) = 72
8x - 24 = 72 add 24 to both sides
8x = 96 divide both sides by 8
X = 12
Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3
<u>Solution:</u>
We have been given two equations which are as follows:
3x - 4y = -24 ----- eqn 1
x + 4y = 8 -------- eqn 2
We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.
We rearrange eqn 2 as follows:
x + 4y = 8
x = 8 - 4y ------eqn 3
Now we substitute eqn 3 in eqn 1 as follows:
3(8 - 4y) -4y = -24
24 - 12y - 4y = -24
-16y = -48
y = 3
Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:
x = 8 - 4(3)
x = 8 - 12 = -4
Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.
The second one is bigger as the square is a even number with the negative whole
(8+6)/(7+8+6)
=14/21
=0.67
=67%
So, the fraction of races that he won was:
: you need ti divide the number of occurrences by the number of possibilities.
We can simplify this:
.
When we write it in decimals until the closest place, it's:
0.167 or 16.667%
