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Mariulka [41]
3 years ago
5

How to graph a standard form equation

Mathematics
1 answer:
Svetach [21]3 years ago
5 0
This formule is
ax + bx = c
ex
y =2x - 4
-2x + y = -4
-( -2x + y = -4)
2x - y = 4
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Which sentence contains a pronoun with an unclear, a missing, or a confusing antecedent?
Arte-miy333 [17]

Answer:

B. They say that doing homework leads to his success in school.

Step-by-step explanation:

Looking at the answers, C and D already make sense, so they're not the answers. The answer A does not have an unclear antecedent because "my mom and me" would not be written as "my mom and I". B is the only answer left. If you look at the sentence, it begins with "they", and it ends up saying "his success in school". This sentence includes a confusing antecedent because the sentence does not define the person who it is describing.

Sorry if this explanation was confusing. I hope this helps! Have a great day!! C:

6 0
3 years ago
SOMEONE PLEASE HELP ME I WILL GIVE BRAINLIST TO THE PERSON WHO GIVES ME THE CORRECT ANSWER
inysia [295]

Answer:

agree

Step-by-step explanation:

8 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
3 years ago
Solve the equation. 4n−18=52
Margaret [11]
How to solve this: (in case you need it)
4n-18=52
4n-18+18=52+18
4n=70
4n/4=70/4
n=35/2
6 0
3 years ago
Read 2 more answers
Can somebody help me out
Alex_Xolod [135]
First one is C (18 sq units)

Second one is A (12sq2 units)
7 0
3 years ago
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