3 years ago

How to graph a standard form equation

Mathematics

1 answer:

Svetach [21]3 years ago

5 0

This formule is
ax + bx = c
ex
y =2x - 4
-2x + y = -4
-( -2x + y = -4)
2x - y = 4

You might be interested in

Solve 2x + 3y = C, for y

natta225 [31]

Answer:

y= $\frac{c-2x}{3}$

Step-by-step explanation:

2x+3y=C

isolate y

3y=C-2x

y= $\frac{c-2x}{3}$

6 0

3 years ago

Read 2 more answers

13. Nathan completed 60% of the passes he attempted during the last football season. If he attempted 90 passes, how many did he

shutvik [7]

Answer:

54 passes

Step-by-step explanation:

90 x 0.6 = 54

5 0

2 years ago

Factor –8x3 – 2x2 – 12x – 3 by grouping. what is the resulting expression? (2x2 – 3)(4x 1) (–2x2 – 3)(–4x 1) (2x2 – 3)(–4x 1) (–

myrzilka [38]

The factors of the expression are $\rm (4x+1)(-2x^2-3)$

<h3>How to find factors in the expression?</h3>

First group the first two terms and the last two terms together respectively.

The factors of the expression are given by;

$\rm -8x^3 -2x^2 - 12x - 3\\\\-2x^2(4x+1)-3(4x+1)\\\\(4x+1)(-2x^2-3)$

Hence, the factors of the expression are $\rm (4x+1)(-2x^2-3)$ .

To know more about factors click the link given below.

brainly.com/question/9645056

5 0

2 years ago

Read 2 more answers

Mathematical expression

Over [174]

Answer: has no equal sign

7 0

3 years ago

Read 2 more answers

(x-1)(x-3)(x+5)(x+7)=297

mihalych1998 [28]

First simplify the expression into polynomial form,

$(x-1)(x-3)(x+5)(x+7)=297$

$x^4+8x^3-10x^2-104x+105=297$

$x^4+8x^3-10x^2-104x-192=0$

Now factor into,

$(x-4)(x+8)(x^2+4x+6)=0$

Which means the solutions are,

$x-4=0\implies\boxed{x_1=4}$

$x+8=0\implies\boxed{x_2=-8}$

and then two complex solutions because determinant of the third factor $D\lt0$ ,

$x^2+4x+6=0$

$x^2+4x+4=-2$

$(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}$

Hope this helps :)

5 0

3 years ago

Read 2 more answers