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The step in which Yvonne first makes an error while solving the quadratic equation by completing the square in step 1.
<h3>What is a quadratic equation?</h3>A quadratic equation is an equation in which the highest power of the variable is two.
Yvonne is solving the quadratic equation, which is,
6x² +24x +7 =0
He is solving the above equation by completing the square.
The first step to solving this quadratic equation by completing the square is, Take the constant value 7 at the opposite side of the equation as,
6x² +24x = -7
Here, the number seven was a positive number, which we have changed to negative because this number brings the other side of the equation.
In the image attached below, the first step of the Yvonne while solving the equation by completing the square is,
6x² +24x = 7
Here, Yvonne does not change the sign of the number 7 while taking it to another side of the equation.
Hence, the step in which Yvonne first makes an error while solving the quadratic equation by completing the square is step 1.
The table is attached with the answer below
Learn more about the quadratic equation here;
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*The dot plot is shown in the attachment below
Answer:
2
Step-by-step explanation:
Interquartile range is the difference between the upper median (Q3) and the lower median (Q1).
First, let's write out each value given in the data. Each dot represents a data point.
We have:
2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7
=>Find the median:
Our median is the middle value. The middle value is the 6th value = 4
==>Upper median Q3) = the middle value of the set of data we have from the median to our far right.
2, 3, 3, 4, 4, |4,| 4, 5, [5], 6, 7
Our upper median = 5
==>Lower median(Q1) = the middle value of the data set we have from our median to our far left.
2, 3, [3], 4, 4, |4,| 4, 5, 5, 6, 7
Lower median = 3
==>Interquartile range = Q3 - Q1 = 5-3 = 2
