Answer: ![46x^2+73x+15](https://tex.z-dn.net/?f=46x%5E2%2B73x%2B15)
Step-by-step explanation:
The area of a rectangle can be calculated with the formula:
![A=lw](https://tex.z-dn.net/?f=A%3Dlw)
l: the length of the rectangle.
w: the width of the rectangle.
The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.
Knowing that the dimensions of the wall are
by
, its area is:
![A_w=(6x+7)(8x+5)\\\\A_w=48x^2+30x+56x+35\\\\A_w=48x^2+86x+35](https://tex.z-dn.net/?f=A_w%3D%286x%2B7%29%288x%2B5%29%5C%5C%5C%5CA_w%3D48x%5E2%2B30x%2B56x%2B35%5C%5C%5C%5CA_w%3D48x%5E2%2B86x%2B35)
As they are planning that the dimensions of the mural be
by
, its area is:
![A_m=(x+4)(2x+5)\\\\A_m=2x^2+5x+8x+20\\\\A_m=2x^2+13x+20](https://tex.z-dn.net/?f=A_m%3D%28x%2B4%29%282x%2B5%29%5C%5C%5C%5CA_m%3D2x%5E2%2B5x%2B8x%2B20%5C%5C%5C%5CA_m%3D2x%5E2%2B13x%2B20)
Then the area of the remaining wall after the mural has been painted is:
![A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15](https://tex.z-dn.net/?f=A_%7B%28remaining%29%7D%3DA_w-A_m%5C%5C%5C%5CA_%7B%28remaining%29%7D%3D48x%5E2%2B86x%2B35-%282x%5E2%2B13x%2B20%29%5C%5C%5C%5CA_%7B%28remaining%29%7D%3D48x%5E2%2B86x%2B35-2x%5E2-13x-20%5C%5C%5C%5CA_%7B%28remaining%29%7D%3D46x%5E2%2B73x%2B15)
Answer:
Step-by-step explanation:
The sum of two matrices is the sum of corresponding terms.
![\left[\begin{array}{ccc}3&1&0\\-1&2&4\\9&7&-2\end{array}\right] +\left[\begin{array}{ccc}5&2&4\\1&12&3\\11&3&-2\end{array}\right] =\left[\begin{array}{ccc}8&3&4\\0&14&7\\20&10&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%260%5C%5C-1%262%264%5C%5C9%267%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%262%264%5C%5C1%2612%263%5C%5C11%263%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%263%264%5C%5C0%2614%267%5C%5C20%2610%26-4%5Cend%7Barray%7D%5Cright%5D)
Answer:
- <em> 15</em>
- <em> 42,250</em>
Step-by-step explanation:
The given function is,
![P=40000+300x-10x^2](https://tex.z-dn.net/?f=P%3D40000%2B300x-10x%5E2)
where,
P = the total production of apples,
x = the number of trees added.
As the quadratic function has a negative leading coefficient, so it will open downward and at the vertex the value of function is maximum.
The vertex will be at ![\left(-\dfrac{b}{2a},-f\left(\dfrac{b}{2a}\right )\right)](https://tex.z-dn.net/?f=%5Cleft%28-%5Cdfrac%7Bb%7D%7B2a%7D%2C-f%5Cleft%28%5Cdfrac%7Bb%7D%7B2a%7D%5Cright%20%29%5Cright%29)
The value of the function will be maximum at,
![x=-\dfrac{b}{2a}](https://tex.z-dn.net/?f=x%3D-%5Cdfrac%7Bb%7D%7B2a%7D)
Putting the values,
![x=-\dfrac{300}{2\times (-10)}=\dfrac{300}{2\times 10}=\dfrac{300}{20}=15](https://tex.z-dn.net/?f=x%3D-%5Cdfrac%7B300%7D%7B2%5Ctimes%20%28-10%29%7D%3D%5Cdfrac%7B300%7D%7B2%5Ctimes%2010%7D%3D%5Cdfrac%7B300%7D%7B20%7D%3D15)
So at x=15 or for 15 number of trees the production will be ,maximum.
Putting x=15 in f(x) will yield the maximum production of apples.
![P=40000+300(15)-10(15)^2=42,250](https://tex.z-dn.net/?f=P%3D40000%2B300%2815%29-10%2815%29%5E2%3D42%2C250)
If all the angles are 60 degrees, this is an equilateral triangle. This means that all the sides have the same lengths. Whatever length side a is, b and c have the same length.
Hope this helps :)