Answer:Each Y could equal 12
Step-by-step explanation:
You would divide each side of the equation y 3 to get y^2=144.
Next take the root of both sides to get y= ± 12
After that just separate the solutions and get 12.
(I hope this helps. I tried)
X+4+2x-10=2x+1
3x-6=2x+1
X-6=1
X=7
I'm fairly sure it's C - even as a prediction, if you add (4x2) and (2x2) it's 12 - and the closest is thirteen, adding on the fractions.
Answer:
Rs 38,640
Step-by-step explanation:
<u>Pay attention:</u>
![A = P(1+r/100)^n](https://tex.z-dn.net/?f=A%20%3D%20P%281%2Br%2F100%29%5En)
The principle (p) : Rs 42,000
Rate of interest (r) : 8%
Time (n) : 1 years
Exact Amount (a) : P(1-R/100)^n
Value:
A = 42,000(1 - 8/100)^1
A = 42,000(1 - 2/25)
A = (42,000 * 23)/25
A = 1,680 * 23
A = Rs 38,640
Answer:
A. -3√7/7
Step-by-step explanation:
We have the equation in trigonometry as following:
with (cos x)^2 different from 0, we have:
![\frac{1}{cos^{2}x } = 1 + tan^{2} x](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bcos%5E%7B2%7Dx%20%7D%20%3D%201%20%2B%20tan%5E%7B2%7D%20x)
=> ![tan^{2} x = \frac{1}{cos^{2}x } -1](https://tex.z-dn.net/?f=tan%5E%7B2%7D%20x%20%3D%20%5Cfrac%7B1%7D%7Bcos%5E%7B2%7Dx%20%7D%20-1)
As (cos θ) = √7/4 ≠ 0, so that we can replace θ into the above equation, we could have:
(tan θ)^2 = 1/[(cos θ)^2] -1
=> (tan θ)^2 = ![\frac{1}{(\sqrt{7}/4) ^{2} } -1 = \frac{1}{7/16} - 1](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28%5Csqrt%7B7%7D%2F4%29%20%5E%7B2%7D%20%7D%20-1%20%3D%20%5Cfrac%7B1%7D%7B7%2F16%7D%20%20-%201)
=>(tan θ)^2 = 16/7 - 7/7 = 9/7
<em>=> tan θ = (3√7)/7 </em>
<em>or tan θ = - (3√7)/7 </em>
<em />
As θ is in quadrant IV, so that its tangent has negative value
=> tan θ = -3√7/7
So that the correct answer is A