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3 years ago

What time is 10 minutes before 8:00 in the morning? *

Mathematics

2 answers:

strojnjashka [21]3 years ago

6 0

Answer: 7:50 AM

Step-by-step explanation:

The clock goes to 60 minutes so if you subtract 10 from 8:00 AM

It will start at 7:60

7:60-10 is 7:50

IRISSAK [1]3 years ago

4 0

Answer:

7:50 AM

Step-by-step explanation:

You might be interested in

Find 3 consecutive even integers if their sum decreased by 10 equals -22

Orlov [11]

Three consecutive even integers can be represented by x, (x+2), and (x+4).

(x + (x + 2) + (x + 4)) - 10 = -22 Get rid of the parentheses
x + x + 2 + x + 4 - 10 = -22 Combine like terms (x + x + x) and (2 + 4 - 10)
3x - 4 = -22 Add 4 to both sides
3x = -18 Divide
x = -6
Check you work.

x = -6
x + 2 = -4
x + 4 = -2

(-6 - 4 - 2) - 10 = 22
-12 - 10 = -22

So, your three integers are -6, -4, and -2 .

6 0

4 years ago

What is the solution to this system of linear equations?

OLEGan [10]

Answer: To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations.

Step-by-step explanation: hope this helps

3 0

3 years ago

Can someone please help me on this question I will give brainliest

xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Geometry

Surface Area of a Sphere: SA = 4πr²
Diameter: d = 2r

Step-by-step explanation:

Step 1: Define

SA = 23 in²

Step 2: Find r

Substitute [SAS]: 23 in² = 4πr²
Isolate r term: 23 in²/(4π) = r²
Isolate r: √[23 in²/(4π)] = r
Rewrite: r = √[23 in²/(4π)]
Evaluate: r = 1.35288 in

Step 3: Find d

Substitute [D]: d = 2(1.35288 in)
Multiply: d = 2.70576 in
Round: d ≈ 3 in

4 0

3 years ago

A) Solve 3(x - 5) = 18

Anna [14]

3x_15=18

3x=18+15

3x=33

x=11

8 0

3 years ago

Need help with homework

motikmotik

We have two points describing the diameter of a circumference, these are:

$\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}$

Recall that the equation for the standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

$M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Now, we replace and solve:

$\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}$

The center of the circle is (-8,-7), so:

$\begin{gathered} h=-8 \\ k=-7 \end{gathered}$

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

$r^2=\Delta x^2+\Delta y^2$

In this case, we will solve the delta with the center coordinate and the B coordinate.

$\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}$

Therefore, the equation for the standard form of a circle is:

$\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}$

In conclusion, the equation is the following:

$(x+8)^2+(y+7)^2=25$

4 0

1 year ago