1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
schepotkina [342]
3 years ago
8

Why are joints important

Physics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

Because they help us move if we didn't have joints we would be like a wobbly balloon at a car dealership.

Explanation:

You might be interested in
6. What's a stalactite?
iogann1982 [59]

I think it's d......... Good luck

8 0
3 years ago
Two factors that affect force are:
Kamila [148]

the answer is B) friction and inertia

7 0
4 years ago
Select the community facility which usually has a driving range on the property to practice your swing.
vagabundo [1.1K]

Answer:

golf course

Explanation:

i will give you all the answers you desire, my love

3 0
3 years ago
An inclined plane makes an angle of 30.0º with the horizontal. 
Wittaler [7]

The force required to push the box upward is 145.3N and the force to pus the box downward is -109.3N

Data given;

  • mass = 15kg
  • angle = 30 degree
  • acceleration = 1.2 m/s^2
  • acceleration due to gravity = 9.8 m/s^2

<h3>Force against gravity</h3>

To move the plane upward, the box will move against gravity.

F = F - mgcos X\\&#10;ma = F - mg cosX

Let's solve for F

ma = F - mgcosX\\&#10;15*1.2 = F - 15*9.8 * cos 30\\&#10;18 = F - 127.30\\&#10;F = 18 + 127.30\\&#10;F = 145.3N

<h3>Force towards gravity</h3>

When the force pushes the box down the inclined plane, it moves towards gravity.

F = F + mgcosX\\&#10;ma = F + mgcosX\\&#10;15*1.2 = F + 15*9.8*cos30\\&#10;F = -109.3N

The force required to push the box upward is 145.3N and the force required to push the box downward is -109.3N

Learn more on force across an inclined plane here;

brainly.com/question/11888124

4 0
3 years ago
What charge appears on each plate of a 10.0 μF parallel plate capacitor, when it is charged to 110 V?
elena-14-01-66 [18.8K]

Answer:

charge, q = ± 1.1 mC

Given:

Capacitance, C = 10.0\micro F = 10.0\times 10^{- 6} F

Voltage, V = 110 V

Solution:

The charge on the capacitor plates can be calculated by using the definition of capacitance as :

q ∝ V

where

q = charge

V = potential difference or Voltage

Therefore,

q = CV

Now, charge, q :

q = 10.0\times 10^{- 6}\times 110 = 1100\micro C = 1.1 mC

Therefore, the charge on the positive plate is:

q = + 1.1 mC

the charge on the negative plate is:

q = - 1.1 mC

8 0
3 years ago
Other questions:
  • Elena makes a table to organize the functions of electric motor components.
    16·2 answers
  • A car travels 60 km in the first 2 hours and 68 km in the next 2 hours.
    12·1 answer
  • Show that the relationship between impulse and the change in momentum is another way of stating Newton's second law of motion.
    9·1 answer
  • Starting from 15 m/s, a certain vehicle can accelerate to 60 m/s at a rate of 6 m/s2. What time is required to make this acceler
    9·1 answer
  • True or false ohm's law states that I = R/V ?
    11·1 answer
  • 1.A star has an absolute magnitude of 4 and a surface temperature of 5,000 degrees C. According to the HR Diagram list the type
    12·2 answers
  • Match the following items.
    6·1 answer
  • What is a<br> strain<br> streched to 5 mm?<br> in<br> a<br> wire of length 0.5m
    11·1 answer
  • A 15.0-kg object sitting at rest is struck elastically in a head-on collision with a 10.5-kg object initially moving at 3.0 m/s.
    12·1 answer
  • Please help- Determine the relationship between potential and kinetic energy in a system.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!