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Citrus2011 [14]
3 years ago
11

When the voltage is at a maximum positive value, the current is at a value that is_________.

Physics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive

Explanation:

We know that the relation between the Voltage and the current is given using the Ohm's law, which states that the voltage (V) is directly proportional to the current (I)

Mathematically,

V ∝ I

Hence,

When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive

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A ford F-250 pulls a 1000-kg car with a net force of 2000 N. What is the acceleration of the car A=F/m
vfiekz [6]

Answer:

2ms^2

Explanation:

A = 2000 divided by 1000

A= 2

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3 years ago
Relationship between education and income
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To summarise the findings, in 2012, there is a significant and positive relationship between higher education level and income (i.e., higher education qualifications lead to higher income). ... Next, we examine the incomes of between bachelor's degree and graduate degree holders.
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3 years ago
(Part 1 of 3)
Ksju [112]

1) 1.028 m/s^2

We can solve this part by using Newton's second law:

F=ma (1)

where

F is the net force

m is the mass

a is the acceleration

There are two forces acting on the boat:

F_1= 2.90 \cdot 10^3 N forward

F_2 = 1.69\cdot 10^3 N backward

So the net force is

F=2.90\cdot 10^3-1.69\cdot 10^3=1.21\cdot 10^3 N

We know that the mass of the boat is

m = 1177.5 kg

So we can now use eq.(1) to find the acceleration:

a=\frac{F}{m}=\frac{1.21\cdot 10^3}{1177.5}=1.028 m/s^2

2) 161.0 m

We can solve this part by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

Here we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

Substituting t = 17.7 s, we find the distance covered:

s=0+\frac{1}{2}(1.028)(17.7)^2=161.0 m

3) 18.2 m/s

The speed of the boat can be found with the following suvat equation

v=u+at

where

v is the final velocity

u is the initial velocity

t is the time

a is the acceleration

In this case we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

And substituting t = 17.7 s, we find the final velocity:

v=0+(1.028)(17.7)=18.2 m/s

And the speed is just the magnitude of the velocity, so 18.2 m/s.

6 0
4 years ago
Any four difference between velocity and acceleration​
pychu [463]

Answer:

https://physicsabout.com/acceleration-and-velcoity/

7 0
3 years ago
An elevator cab is pulled directly upward by a single cable. The elevator cab and its single occupant have a mass of 2300 kg. Wh
Murrr4er [49]

Answer:

15.64 KN

Explanation:

mass of the elevator cab with a single occupant= 2300 kg

acceleration relative to the cab a_{ce}= 6.80 m/s^2

acceleration of the coin relative to the cab in the opposite direction of motion of cab so we can consider it as a= -6.80 m/s^2

The acceleration of elevator cab relative to the ground a_{cg}

now we can say that

a_{ce} +a_{eg} =a_{cg}

=-6.80+ a_{eg}= -9.8

[tex]a_{eg}=-9.8+6.80=-3.8

The forces that act on elevator cab are tension and gravitational, applying newtons second law

T- mg= ma_{eg}

Then the tension in the cable is

T= 2300(-3.8)+2300×9.8=  15640 N= 15.64 KN

therefore tension in the string will be 15.64 KN

3 0
4 years ago
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