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Kamila [148]
3 years ago
7

A force of 20 N acted on a 5 kg object, moving it a distance of 4 m. How much work was done on the object?

Physics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

400J

Explanation:

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Explanation:

For most temperature scales, the boiling point of water and the freezing point is used to calibrate it.

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Freezing point             273K                            0°C                        32°F

Melting point                373K                          100°C                     212°F

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A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.20 m,
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Answer:

F=2627.6N

Explanation:

The work done by this resistive force while traveling a distance <em>d</em> underwater would be:

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This work is equal to the change of mechanical energy. At the diving plataform and underwater, when she stops moving, the woman has no kinetic energy, so all can be written in terms of her total change of gravitational potential energy:

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Putting all together:

F=-\frac{W}{d}=-\frac{mg(h_f-h_i)}{d}=-\frac{(65kg)(9.8m/s^2)(-3.2m-10m)}{3.2m}=2627.6N

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