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3 years ago

1. Evaluate each expression:

Mathematics

2 answers:

Nastasia [14]3 years ago

6 0

Answer:

....

Step-by-step explanation:

skelet666 [1.2K]3 years ago

5 0

Answer:

a. −12•13= -156

b. −12•−13= 156

c. 12•(−54) = -648

d. −12•(−54) = 648

Step-by-step explanation:

a and c have negative

b and d have positive

hope this helps ;)

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Sladkaya [172]

<h2>Hello!</h2>

The answer is:

The correct option is:

A) $74.55

To calculate how much does Sonya pay for the four pairs altogether, we need to calculate the original price after the 50% discount and the taxes.

Calculating we have:

$PriceAfterDiscount=35*50(percent)=35*\frac{50}{100}\\\\35*\frac{50}{100}=35*0.5=17.5$

We have that before the tax, the price of the shoes was $17.5, then, calculating the price after the taxes, we have:

$AfterTaxes=17.5(1+6.5(percent))=17.5(1+\frac{6.5(percent)}{100})\\\\AfterTaxes=17.5(1+\frac{6.5(percent)}{100})=17.5*(1+0.065)\\\\AfterTaxes=17.5*(1+0.065)=17.5*1.065=18.637$

So, we have that the price after discount and the taxes is $18.637 per each pair of shoes.

Hence, the price for the four pairs of shoes will be:

$TotalPrice=4*18.637=74.548=74.55$

Have a nice day!

8 0

3 years ago

2x < 6<br><br> Plz help plzzzz

Nat2105 [25]

Answer:

2x < 6

x < 3

Step by step:

2x < 6

x < 3

5 0

3 years ago

Read 2 more answers

Darlene has a balance of $3980 on a credit card with an APR of 22.8%. Paying off her balance in which of these lengths of time w

inna [77]

Answer:

The correct answer is D. 5 months

Step-by-step explanation:

Balance = P = $3980

Rate (r) = 22.8% ,

n is no. of times interest is calculated in one year n = 1

$Interest=P\cdot (1+\frac{r}{n\times 100})^{n\times time}\\\\\textbf{time = t = 8 months = }\frac{8}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{8}{12}}\\\\Interest=3980\times 1.228^{\frac{8}{12}}\\\\\implies Interest=\$\thinspace 4564.03\\\\\textbf{time = t = 6 months = }\frac{6}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{6}{12}}\\\\Interest=3980\times 1.228^{\frac{6}{12}}\\\\\implies Interest=\$\thinspace 4410.44$

$\textbf{time = t = 9 months = }\frac{9}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{9}{12}}\\\\Interest=3980\times 1.228^{\frac{9}{12}}\\\\\implies Interest=\$\thinspace 4642.82\\\\\textbf{time = t = 5 months = }\frac{5}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{5}{12}}\\\\Interest=3980\times 1.228^{\frac{5}{12}}\\\\\implies Interest=\$\thinspace 4335.60$