1 4 7 I think
I don’t know for sure though
√200 = √2·100 = √2 · √100 = 10√2
Answer:
+120/169 or -120/169
Step-by-step explanation:
- let
![cos^{-1}[\frac{5}{13} ] = \alpha](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B13%7D%20%20%5D%20%3D%20%5Calpha)
where, alpha is some angle that satisfies the assumed condition.
- so,
[ taking cos to the other side or applying cos on both sides]
- now, substitute this in the given expression
as sin
= 
[by general trigonometry formula: ![cos^{2}[\beta] +sin^{2}[\beta]=1](https://tex.z-dn.net/?f=cos%5E%7B2%7D%5B%5Cbeta%5D%20%20%2Bsin%5E%7B2%7D%5B%5Cbeta%5D%3D1)
]
so if , we can get sin
from the above formula as + or - 12/13
(because, after taking square root on both sides we keep + or -]
- as, sin
![2\beta = 2*sin[\beta ]*cos[\beta ]](https://tex.z-dn.net/?f=2%5Cbeta%20%20%3D%202%2Asin%5B%5Cbeta%20%5D%2Acos%5B%5Cbeta%20%5D)
[by general trigonometry formula]
- here, now
![sin[2\alpha ]=2*(+or- 12/13)*5/13\\](https://tex.z-dn.net/?f=sin%5B2%5Calpha%20%5D%3D2%2A%28%2Bor-%2012%2F13%29%2A5%2F13%5C%5C)
so, the final value can be 120/169 or -120/169.
Answer:
10 feet
Step-by-step explanation:
This is a problem of scale
where scale is
actual height of any object/ height of that object on drawing
given
actual height = 24 feet
this is represented 1/2 inch on drawing
thus
scale = actual height/ height on drawing = 24 feet/1/2 inch = 24*2 feet/ 1 inch
scale = 48 feet / 1 inch
given actual height of a building = 480 feet
let the height on drawing be x inch
thus
48 feet / 1 inch = 480 feet/ x inch
=> x inch/ 1 inch = 480 feet / 48 feet
=> x = 10 feet
Thus, the height of building on the drawing is 10 feet
Answer:
B. i took the lil question on edge, hope this helps
Step-by-step explanation:
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