Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99
Step-by-step explanation: Ok, so let's put the data set from least to greatest....
(63, 63, 76,) (77, 79,) (84, 99, 99)
First Quartile Third Quartile
First, let's find the median, since you made a little mistake...
77 + 79 = 156
156 ÷ 2 = 78
The median is 78!
Now, let's determine the first quartile and the third quartile.
For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...
First Quartile: 63
Third Quartile: 99
I hope this helps!
Answer:
Container B has smaller surface area.
Step-by-step explanation:
Given:
Container A
Radius = 60/2 = 30 mm
Height = 4 x 60 = 240 mm
Container B
Length = 120
Width = 120
Height = 60
Computation:
Surface area of container A (Cylinder) = 2πr[h+r]
Surface area of container A (Cylinder) = 2[22/7][60][120+60]
Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)
Surface area of container B (Cuboid) = 2[lb+bh+hl]
Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]
Surface area of container B (Cuboid) = 57,600 mm²
Container B has smaller surface area.
Answer:
The distance he traveled is 17.69.
Step-by-step explanation:
Simple you'll need to multiply 12.2 times 1.45. Which should equal a total distance of 17.69
<span>The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides </span>⇒
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10/12 = (3x+2)/(5x-0.4)
10(5x-0.4) = 12(3x+2)
50x - 4 = 36x + 24
50x - 36x = 24 + 4
14x = 28
x = 28/14
x = 2
QS = 3x + 2 = 3*2 + 2 = 6 + 2 = 8
SR = 5x - 0.4 = 5*2 - 0.4 = 10 - 0.4 = 9.6
Answer is QS=8, SR=9.6
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