Answer:
Note the fragments from DdeI restriction –
I. AA individuals have two copies of normal b-globin allele.
b-globin allele ----DdeI-----------> 176 bp + 201 bp + 600 bp
Since there are two copies of b-globin allele, the restriction of AA genome would produce 2 copies each of 176 bp, 201 bp and 600 bp fragments.
II. AS individuals have one normal and one mutated copy b-globin allele. So, following fragments would be obtained -
b-globin allele ----DdeI-----------> 176 bp + 201 bp + 600 bp
b-globin allele ----DdeI-----------> 376 bp + 600 bp
So, for such genotype, four fragments of MW as shown above would be produced.
III. SS individuals have two mutated copy b-globin allele. So, following fragments would be obtained -
b-globin allele ----DdeI-----------> 376 bp + 600 bp
So, for such genotype, two copies each of the fragments of MW as shown above would be produced.
