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igor_vitrenko [27]
3 years ago
11

Natalie works in a shop and earn $43 per day. She earns an extra $3 for each toy she sells. If Natalie wants to earn at least $7

0 per day, which ineaquality shows the minimum number of toys, n, that she should sell?
Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0
70-43=27
27 divided by 3=9

She needs to sell 9 toys

Hope this helps!
Pachacha [2.7K]3 years ago
7 0
<span>This would be your answer 43 + 3n ≥ 70, so n ≥ 9

I hape this help</span>
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Answer:

9 hours and 10 minutes

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Whats the diffrence of 2 2/3 - 1 2/5 write answer in simplest form
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2 \frac{2}{3}-1 \frac{2}{5}=2 \frac{2 \times 5}{3 \times 5}-1 \frac{2 \times 3}{5 \times 3}=2 \frac{10}{15}-1 \frac{6}{15}=\boxed{1\frac{4}{15}}
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How do you solve 4(4+363562-75635)(4)/53
Mice21 [21]

Simple, use PEMDAS and then do your simple  math and then your answer should be 86922.56604

4 0
3 years ago
There are 7 acts in a talent show.
lara31 [8.8K]

Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

7 0
4 years ago
in 1991, a gallup poll reported this percent to be 79%. using the data from this poll, test the claim that the percent of driver
snow_lady [41]

We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.

Given,

The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.

In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.

To report the large-sample z statistic and its p-value,

Null hypothesis,

H₀ : p = 0.79

Alternative hypothesis,

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Level of significance, α = 0.01

Under H₀

Test statistic,

Z_0= \frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n} }  }

Z₀ = -7.948

The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by

P-value = P(z <-7.945)

            = 0.000     (from z-table)

Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.

To learn more about hypothesis click here:

brainly.com/question/17173491

#SPJ4

5 0
1 year ago
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