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2 years ago

Solve for the given variable

Mathematics

2 answers:

Natalija [7]2 years ago

7 0

Answer:

k = 30

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

120° is an exterior angle of the triangle, thus

k + 90 = 120 ( subtract 90 from both sides )

k = 30

Ne4ueva [31]2 years ago

3 0

Answer:

Step-by-step explanation:

Well we know the first angle is 90 degrees, which means we have 90 degrees left to work with. Then, the top angle would be 60 degrees, because there is a straight line (which of course has to equal 180), so 180-120 = 60. Now, 90-60=30!

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Twenty times a square of a positive integer plus 50 equals negative 40 times the square of the positive integer plus one-hundred

Dmitrij [34]

Let "x" be the positive integer
Twenty times a square of a positive integer plus 50:
20x² + 50
Negative 40 times the square of the positive integer plus one-hundred and ten times the positive integer:
-40x² + 100x

The equation could be used is shown below:
20x² + 50 = -40x² +100x
20x² + 40x² -100x + 50 = 0
60x² - 100x +50 =0

3 0

3 years ago

A square has a side length of 6x+2. a rectangle with width 3x+1 has the same area as the square. what is the length of the recta

deff fn [24]

Answer:

Step-by-step explanation:

(6x+2)/(3x+1) = 2

3 0

2 years ago

How many solutions does the equation -2y+2y+3=3have?

Leya [2.2K]

Answer:

multiple, bc if u solve it its all real numbers

Hope This Helps! Have A Nice Day!!

6 0

3 years ago

I’m confused on this one

erastovalidia [21]

In the chart of the triangle it shows that the variable b is the base. It also give us the equation for area 1/2bh (half of base * height)

Now we just plug in the values we are given

1/2bh

1/2(10*13)

1/2(130)

The area of the triangle is 65 ft

4 0

2 years ago

Read 2 more answers

Solve The Equation <br> 4x×9y=7<br> 4x-9y=9

hoa [83]

Answer:

$\large\boxed{x=\dfrac{9}{8}-\dfrac{\sqrt{109}}{8},\ y=-\dfrac{1}{2}-\dfrac{\sqrt{109}}{18}}\\or\\\boxed{x=\dfrac{9}{8}+\dfrac{\sqrt{109}}{2},\ y=-\dfrac{1}{2}+\dfrac{\sqrt{109}}{18}}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}4x\times9y=7&(1)\\4x-9y=9&(2)\end{array}\right\\\\(2)\\4x-9y=9\qquad\text{subtract}\ 4x\ \text{from both sides}\\-9y=-4x+9\qquad\text{change the signs}\\9y=4x-9\qquad\text{substitute it to (1)}\\\\4x(4x-9)=7\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\(4x)(4x)+(4x)(-9)=7\\(4x)^2-36x=7\\(4x)^2-2(4x)(4.5)=7\qquad\text{add}\ 4.5^2\ \text{to both sides}\\(4x)^2-2(4x)(4.5)+4.5^2=7+4.5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2$

$(4x-4.5)^2=7+20.25\\(4x-4.5)=27.25\to 4x-4.5=\pm\sqrt{27.25}\\\\4x-\dfrac{45}{10}=\pm\sqrt{\dfrac{2725}{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{2725}}{\sqrt{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25\cdot109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25}\cdot\sqrt{109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{5\sqrt{109}}{10}\qquad\text{add}\ \dfrac{45}{10}\ \text{to both sides}\\\\4x=\dfrac{45}{10}\pm\dfrac{5\sqrt{109}}{10}$

$4x=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 4}\\\\x=\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\\\\\text{Put the values of}\ x\ \text{to (2):}\\\\9y=4\left(\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\right)-9\\\\9y=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}-\dfrac{18}{2}\\\\9y=-\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 9}\\\\y=-\dfrac{1}{2}\pm\dfrac{\sqrt{109}}{18}$

8 0

2 years ago