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3 years ago

PLS HELP I WILL HELP BACK 15 POINTS WILL GIVE BRAINLIEST Write the equation of a polynomial, in standard form, that has:

Mathematics

1 answer:

djyliett [7]3 years ago

4 0

Answer: -5x^3 -13x^2 -6x + 15ix + 39ix + 18i

Step-by-step explanation:

An equation with zeros at these numbers could be put in form x = number.

So, (x-3) could be set to 0 to get x=3.

So, you can look at these "answers" they give you and work backward to get:

(x-3)(x+2/5)(x-3i)

Multiply first two together.

x^2+2/5x-3x-6/5

simplify

x^2 - 2 3/5x -6/5

Change first term to have same denominator by multiplying by "1" in the form of -5/-5

-5x^2/-5 - 13/5x -6/5

Divide all terms by 1/5 (which is the same as multiplying each term by 5)

(-5x^2 -13x -6)

Now multiply by (x-3i)

-5x^3 -13x^2 -6x + 15ix + 39ix + 18i

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4 to the -4 divided 4 to the -2

Mandarinka [93]

Answer:

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3 years ago

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Solve this problem. -16r=272

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Answer:

-17

Step-by-step explanation:

-16r=272

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3 years ago

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Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form. (2 points) a y = 3x − 7 b y = 3x

sashaice [31]

Answer: y = 5x − 11

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (3,4) and (2, -1),

y2 = - 1

y1 = 4

x2 = 2

x1 = 3

Slope,m = (- 1 - 4)/(2 - 3) = - 5/- 1 = 5

To determine the y intercept, we would substitute x = 3, y = 4 and m= 5 into

y = mx + c. It becomes

4 = 5 × 3 + c

4 = 15 + c

c = 4 - 15 = - 11

The equation becomes

y = 5x - 11

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3 years ago

Where do you put a decimal on 64

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it depends what the question is

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3 years ago

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Solve by completing the square. Round your answers to the nearest tenth and then locate the greater solution. <img src="https://

Andrews [41]

Step-by-step explanation:

Step 1: Write our Givens

${x}^{2} + 10x - 7 = 0$

Move the constant term ,(the term with no variable) to the right side.

Here we have a negative 7, so we add 7 to both sides

${x}^{2} + 10x = 7$

Next, we take the linear coeffeicent and divide it by 2 then square it.

$( \frac{10}{2} ) {}^{2} = 25$

Then we add that to both sides

${x}^{2} + 10x + 25 = 7 + 25$

${ {x}^{2} } + 10x + 25 = 32$

Next, we factor the left,

$(x + 5)(x + 5) = 32$

we got 5 because 5 add to 10 and multiply to 25 as well.

so we get

$(x + 5) {}^{2} = 32$

This is called a perfect square trinomial.

Next, we take the square root of both sides

$x + 5 = ± \sqrt{32}$

± menas that we have a positive and negative solution.

Subtract 5 form both side so we get

$x = - 5± \sqrt{32}$

The greater solution is when sqr root of 32 is positive so the answer to that is

$\sqrt{32} - 5 = 0.7$

3 0

2 years ago