Answer: -5x^3 -13x^2 -6x + 15ix + 39ix + 18i
Step-by-step explanation:
An equation with zeros at these numbers could be put in form x = number.
So, (x-3) could be set to 0 to get x=3.
So, you can look at these "answers" they give you and work backward to get:
(x-3)(x+2/5)(x-3i)
Multiply first two together.
x^2+2/5x-3x-6/5
simplify
x^2 - 2 3/5x -6/5
Change first term to have same denominator by multiplying by "1" in the form of -5/-5
-5x^2/-5 - 13/5x -6/5
Divide all terms by 1/5 (which is the same as multiplying each term by 5)
(-5x^2 -13x -6)
Now multiply by (x-3i)
-5x^3 -13x^2 -6x + 15ix + 39ix + 18i
