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olga_2 [115]
3 years ago
14

PLS HELP I WILL HELP BACK 15 POINTS WILL GIVE BRAINLIEST Write the equation of a polynomial, in standard form, that has:

Mathematics
1 answer:
djyliett [7]3 years ago
4 0

Answer:  -5x^3 -13x^2 -6x + 15ix + 39ix + 18i

Step-by-step explanation:

An equation with zeros at these numbers could be put in form x = number.

So, (x-3) could be set to 0 to get x=3.

So, you can look at these "answers" they give you and work backward to get:

(x-3)(x+2/5)(x-3i)

Multiply first two together.

x^2+2/5x-3x-6/5

simplify

x^2 - 2 3/5x -6/5

Change first term to have same denominator by multiplying by "1" in the form of -5/-5

-5x^2/-5 - 13/5x -6/5

Divide all terms by 1/5 (which is the same as multiplying each term by 5)

(-5x^2 -13x -6)

Now multiply by (x-3i)

-5x^3 -13x^2 -6x + 15ix + 39ix + 18i

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For f(x) = 3x + 1 and g(x) = x^2 - 7, find f(g(4)).
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First, let's find g(4). After we find it, we can substitute the value into f(x).


To find g(4), we need to substitute x = 4 into the function g(x), as shown below:

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Now that we have found g(4) = 9, we can substitute this value in for x in f(x).

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F(x) = x^2 is stretched vertically by a factor of 4 and shifted 1 unit down.<br><br> equation = ???
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Answer:

f(x) = 4x² - 1

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