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3 years ago

14

A parallelogram has an area of 37.72 m² and a height of 4.6 m. How long is the base of the parallelogram?

1 answer:

sergeinik [125]3 years ago

3 0

Answer:

8.2m

Step-by-step explanation:

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What is 280 as a fraction? Show your work.

Katen [24]

Any number divided by 1 is still that number (it stays the same).
So you can rewrite 280 as 280/1, which is a fraction.

With 280/1, you can also get an equivalent fraction by multiplying the numerator and denominator by a number, let's say 2.
So multiplying the numerator 280 by 2 would get 560, the denominator would be 2. So another equivalent fraction would be 560/2

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12

Step-by-step explanation:

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Put the following correlation coefficients in order from weakest to strongest in terms of strength of linear association.

asambeis [7]

Answer:

0.137 ->0.339 -> -0.431 -> 0.869 -> -0.903

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To win a game, you need at least 45 points. Each question is worth 3 points. Write and solve an inequality that represents the n

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3x=45
(divide each side by 3)
x=15
You need to answer 15 correctly.

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The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to

katovenus [111]

Answer:

$A' = (1,2)$

$B'=(2,1)$

$C' =(3,3)$

Step-by-step explanation:

Given

$A = (3,6)$

$B = (6,3)$

$C = (9,9)$

$Scale = \frac{1}{3}$

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:

$A = (3,6)$ $B = (6,3)$ $C = (9,9)$

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.

$(A'B'C') = Scale\ Factor * (ABC)$

$A' = \frac{1}{3} * A$

$A' = \frac{1}{3} * (3,6)$

$A' = (\frac{3}{3},\frac{6}{3})$

$A' = (1,2)$

$B' = \frac{1}{3} * B$

$B' = \frac{1}{3} * (6,3)$

$B' = (\frac{6}{3},\frac{3}{3})$

$B'=(2,1)$

$C' = \frac{1}{3} * C$

$C' = \frac{1}{3} * (9,9)$

$C' = (\frac{9}{3},\frac{9}{3})$

$C' =(3,3)$

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3 years ago