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2 years ago

Help Plzzz! Convert 122lbs to Kilograms and plz show how you got the answer!!!!!!

Mathematics

2 answers:

PolarNik [594]2 years ago

4 0

Answer:

55.83

Step-by-step explanation:

Divide the number of pounds by 2.2046 to use the standard equation.

Vanyuwa [196]2 years ago

4 0

Answer:

55.34 kg

Step-by-step explanation:

1 kg = 2.204 lbs

then

$122 lbs\times \frac{1 \: kg}{2.204 \: lbs}$

because lbs from the numerator will goes with lbs in the denominator the only unit remains is kg

122 ÷ 2.204 kg = 55.34 kg

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Six and forty-two ten-thousandths as a decimal

sergey [27]

Answer:

6.0042

Step-by-step explanation:

6 and forty-two ten-thousandths as a decimal.

mixed number : $6\frac{42}{10,000}$

decimal : 6.0042

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3 years ago

Complete the square to solve 4x2 + 24x = 4.

igomit [66]

Answer:

x = - 3 ± $\sqrt{10}$

Step-by-step explanation:

Given

4x² + 24x = 4 ( divide through by 4 )

x² + 6x = 1

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = 1 + 9

(x + 3)² = 10 ( take the square root of both sides )

x + 3 = ± $\sqrt{10}$ ( subtract 3 from both sides )

x = - 3 ± $\sqrt{10}$

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2 years ago

Read 2 more answers

Which ordered pairs are solutions to the inequality 4x+y>-6

Lilit [14]

Answer:

(-1.5, 0) and (0, -6)

Step-by-step explanation:

3 0

2 years ago

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A regular pentagon has side lengths of 10 cm and an

Fittoniya [83]

Answer: 172 square centimeters.

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a pentagon (A) = 1/2× 5s × a

Where:

s : side of the pentagon

a: apothem

Replacing with the values given and solving for A (area):

A =1/2 x (5 x10) x 6.88

A = 172 square centimeters.

Feel free to ask for more if needed or if you did not understand something.

7 0

2 years ago

(csc x - 1) (csc x + 1)

victus00 [196]

<h2>Explanation:</h2>

Here we have the following expression:

$(csc x - 1) (csc x + 1)$

So we need to extend this. Remember that the difference of squares tells us:

$(a-b)(a+b)=a^2-b^2$

So here:

$a=cscx \\ \\ b=1$

Thus:

$(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}$

4 0

3 years ago