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4 years ago

What is the center and radius of the circle that has the equation x+72+y-42=49? Explain.

Mathematics

1 answer:

balu736 [363]4 years ago

3 0

Answer: The center is (-7, 4) and the radius is 7.

Step-by-step explanation:

The equation for a circle usually is:

(x - a)^2 + (y - b)^2 = R^2

where R is the radius, and (a, b) is the center of the circle.

I guess that the equation in this case is:

(x + 7)^2 + (y - 4)^2 = 49

then, in this case we have:

a = -7 and b = 4, then (a, b) = (-7, 4)

this means that the center of our circle is in the point (-7, 4)

and we know that:

R^2 = 49

R = √49 = 7

Then the radius is equal to 7.

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Read 2 more answers

If triangle ABC is similar to triangle DEC, find the values of x and y.

Mumz [18]

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal, it is obtained by Pythagoras theorem.

Step-by-step explanation:

The given are,

From ΔABC,

AB= 6

BC= 10

AC = x

From ΔDEC,

CD= 28

DE= 21

CE = y

Step:1

Pythagoras theorem from ΔABC,

$BC^{2}=AB^{2} + AC^{2}$ ...............(1)

Substitute the values,

$10^{2}$ = $6^{2}$ + $AC^{2}$

100 = 36 + $AC^{2}$

$AC^{2}$ = 100 - 36

= 64

AC = $\sqrt{64}$

AC = 8

AC = x = 8

Step:2

Pythagoras theorem for ΔDEC,

$CE^{2} = CD^{2} + DE^{2}$ ................(2)

From the values,

$CE^{2}$ = $28^{2}$ + $21^{2}$

$CE^{2}$ = 784 + 441

= 1225

CE = $\sqrt{1225}$

CE = 35

CE = y = 35

Result:

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal.

5 0

3 years ago