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jeka57 [31]
4 years ago
11

The perimeter of the rectangular playing field is 320 yards. the length of the field is 4 yards less than triple the width. what

are the dimensions of the playing field
Mathematics
1 answer:
fgiga [73]4 years ago
8 0
Let the width be X
Then the length is X + 70
The perimeter is the sum of all sides
There are 2 widths (left side and right side) and 2 lengths (top and bottom)
Perimeter = 2 * width + 2 * length
Perimeter = 2 * X + 2 * (X+70)
Perimeter: 2 X + 2 X + 140 = 380
4 X = 380-140
4 X = 240
X = 240 / 4
X = 60
Width = 60 - the smaller of two sides
Length = X + 70 = 60 + 70 = 130 - the larger of two sides


Check:
<span> 2 * 60 + 2 * 130 = 380 </span>
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scZoUnD [109]

Answer:

14in approx

Step-by-step explanation:

Given data

number of rotations= 10

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cross multiply

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x=  87.92 inches

This means that the circumference of the  tire is 87.92 in

From

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8 0
3 years ago
HELPPP !! If O N = 8 x − 8 , L M = 7 x + 4 , N M = x − 5 , and O L = 3 y − 6 , find the values of x and y for which LMNO must be
sveticcg [70]

Answer:

x=12 and y=4.3

Step-by-step explanation:

Given the sides of quadrilateral that are  O N = 8 x − 8 , L M = 7 x + 4 , N M = x − 5 , and O L = 3 y − 6. we have to find the value of x and y so that LMNO  be a parallelogram.

we know opposite sides of parallelogram are equal.

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Equating opposite sides equal, we get

8x-8=7x+4 ⇒ 8x-7x=8+4=12 ⇒ x=12

implies, NM=x-5=12-5=7

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3 years ago
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6 0
3 years ago
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Alenkasestr [34]

Answer:

Step-by-step explanation:

If divided: 0.38461538461

If percent: 38.4615%.

Brainliest rn:D

4 0
3 years ago
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Phoenix [80]

we know that

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in this problem we have

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<u>the answer is</u>

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