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2 years ago

If u had to choose where would u go Splashtown or the JW Marriott suit S.A Hill country resort and spa

Mathematics

2 answers:

miskamm [114]2 years ago

7 0

Answer:

splashtown

Step-by-step explanation:

Hoochie [10]2 years ago

3 0

Answer: splashtown
Explanation:

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A bag contains three red marbles, two green ones, one lavender one, four yellows, and five orange marbles. HINT [See Example 7.

kirill115 [55]

Answer:

There are 12 sets of four marbles include all the red ones.

Step-by-step explanation:

Given : A bag contains three red marbles, two green ones, one lavender one, four yellows, and five orange marbles.

To find : How many sets of four marbles include all the red ones?

Solution :

Number of red marbles = 3

Number of green marbles = 2

Number of lavender marbles = 1

Number of yellow marbles = 4

Number of orange marbles = 5

We have to form sets of four marbles include all the red ones,

For position of getting red ones we have three red marbles i.e. $^3C_3$

For the fourth one we have 12 choices i.e. $^{12}C_1$

Total sets of four marbles include all the red ones is

$=^3C_3\times ^{12}C_1$

$=1\times 12$

$=12$

Therefore, There are 12 sets of four marbles include all the red ones.

5 0

2 years ago

Mrs. Jackson made a line plot of the times it took students to complete a project.

Komok [63]

This value is very different from the other values

8 0

3 years ago

PLS HELPS!! THIS IS WORTH 200 PTS!! FIRST ONE ASNWERS CORRECTLY, GETS THE BRAINIEST.

Verizon [17]

Answer:

B) −2

Explanation:

When x is positive then y is positive integer.

When x is negative then y is negative integer.

For Option A

y = 2(-3) + 5

y = -1 [x is negative so is y]

For Option B

y = 2(-2) + 5

y = 1 [x is negative but y is positive]

For Option C

y = 2(1) + 5

y = 7 [x is positive so is y]

For Option D

y = 2(2) + 5

y = 9 [x is positive so is y]

8 0

2 years ago

Read 2 more answers

How many complex zeros does the polynomial function have? f(x)=−3x^6−2x^4+5x+6

REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have

it goes like this:

for a polynomial with real coefients, consider $f(x)=-3x^6-2x^4+5x+6$ .

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root

to get the negative roots, we evaluate f(-x) and see how many times the root changes

$f(-x)=-3x^6-2x^4-5x+6$

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root

a total of 2 real roots

a function of degree $n$ can have at most, $n$ roots

our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots

you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0

2 years ago

8w-15=57 two step equations

insens350 [35]

Answer:

w=9

Step-by-step explanation:

Our equation is: 8w-15=57

Add 15 to both sides

-15 is now gone because we added 15 so it would be zero

and we have 72 because 15 plus 57 is 72

Now we have:

8w=72

Divide by 8 on both sides

8w cancels out to just w

and 72 divided by 8 is 9

And you're left with:

w=9

7 0

3 years ago