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Pachacha [2.7K]
2 years ago
14

Determine whether y varies directly with x. If so, find the constant of variation and write the function rule.

Mathematics
1 answer:
Alexeev081 [22]2 years ago
4 0
Yes they are, the constant variation is that for every 3 added to the x side, 1 is added to the y side. I would really appreciate the brainliest mark thanks!
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I need help on my math
Alina [70]
#1 is three feet
#2 is 400 feet and #4 a is 2 cm sq. And b is 2.5 cm sq.
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2 years ago
invent three meaningful algebatric expressions of your own from the list of variables and enter them into the table below.write
Mars2501 [29]

Answer:

49

Step-by-step explanation:

4 0
2 years ago
5/6 N=10 solve this problem. I could not put the six under the five where it belongs. please show the work
Andreyy89

5/6N = 10

Mutiply by 6/5

So N=12

3 0
3 years ago
Y = –3x – 5 help I don’t know the answer please
earnstyle [38]

Answer:

x=-5/3

Step-by-step explanation:

Add 5 to both sides to get 5=-3x.

Then divide by -3.

And get -5/3=x

6 0
2 years ago
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
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