-dB/dt = kAB = k(2B)(B) = 2kB^2
-dB/B^2 = 2kdt
Integrating: 1/B - 1/(B_0) = 2kt
At t = 10, if 15 g of C have formed, this must have consumed 10 g A and 5 g B. The remaining mass of B is 45 g.
1/45 - 1/50 = 2(k)(10)
k = 1.11 x 10^-4
Then substituting this value of k with t = 40:
1/B - 1/50 = 2(1.11 x 10^-4)(40)
1/B - 1/50 = 0.008889
1/B = 0.028889
B = 34.62 g remaining
Therefore, 50 - 34.62 = 15.38 g of B have been consumed.
Doubling, 30.76 g of A have been consumed.
This means that 15.38 + 30.76 = 46.15 g of C have been formed.
Electrons - each atom has its own unique #
<u>Answer:</u> The pH of the solution is 1.41
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

Given mass of perchloric acid = 581.1 mg = 0.5811 g (Conversion factor: 1 g = 1000 mg)
Molar mass of perchloric acid = 100.5 g/mol
Volume of solution = 150 mL
Putting values in above equation, we get:

1 mole of perchloric acid produces 1 mole of
ions and 1 mole of
ions
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
![[H^+]=0.0385M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.0385M)
Putting values in above equation, we get:

Hence, the pH of the solution is 1.41