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2 years ago

If you take a 15.0-mL portion of the stock solution and dilute it to a total volume of 0.600 L , what will be the concentration

of the final solution?

Chemistry

1 answer:

alexira [117]2 years ago

6 0

$15 \div .6$

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Predict the bond angle in metgane using vsepr theory

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Bond Angle in the molecule of Methane according to the VSEPR theory is that it has a bond angle of 109.5 degrees with respect to the Carbon and the Hydrogen

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Salt is an ionic compound that is produced when a cation and an anion from an acid-base reaction combine, and solutions of salts

Andrej [43]

Answer:

a. True

Explanation:

The statement given regarding salt is correct,

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2 years ago

For the reaction

azamat

Answer:

Mass = 5.56 g

Explanation:

Given data:

Mass of Cl₂ = 4.45 g

Mass of NaCl produced = ?

Solution:

Chemical equation:

2Cl₂ + 4NaOH → 3NaCl + NaClO₂ + 2H₂O

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 4.45 g/ 71 g/mol

Number of moles = 0.063 mol

Now we will compare the moles of Cl₂ with NaCl.

Cl₂ : NaCl

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7 0

2 years ago

Question 6 (3 points)

olga55 [171]

Answer:

Explanation:

Given parameters:

Molarity of KOH = 0.26M

Volume of H₂SO₄ = 19.76mL

Molarity of H₂SO₄ = 0.20M

Unknown:

Volume of KOH = ?

Solution:

This is a neutralization reaction in which an acid reacts with a base to produce salt and water:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

We solve from the known to the unknown in the reaction.

The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:

Number of moles of acid = molarity x volume

Number of moles of acid = 19.76 x 0.20 = 3.95mol

From the balanced reaction equation:

1 mole of acid reacts with 2 moles of the bases KOH

3.95mole of acid would react with 3.95moles x 2 of the base

Number of moles of reacting base = 7.90moles

To find the volume of base;

Volume of base = $\frac{number of moles of base}{molarity}$

Volume = $\frac{7.90}{0.26}$ = 30.40mL

Learn more:

Neutralization brainly.com/question/6447527

#learnwithBrainly

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2 years ago