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Gnoma [55]
4 years ago
8

If TU = S + 22 and VX = s, what is the value of s?

Mathematics
2 answers:
yuradex [85]4 years ago
4 0

Answer:

s is 22

Step-by-step explanation:

Notice that we are dealing with two similar triangles (UTW and XVW) which have the characteristic that the sides of the larger one are twice the size of the smaller triangle's sides.  TW = 2 XW, UW = 2 VW, and therefore TU = 2 VX

then we use the expressions they gave us for TU and for VX in the equation above:

TU = 2  VX

s + 22 = 2 * s

subtract s from both sides:

22 = 2 s - s

22 = s

Therefore, s is 22.

Elodia [21]4 years ago
3 0

Answer:

nose no eh visto ese tema

Step-by-step explanation:

nose no eh visto ese tema

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If correct I will give brainly​
Marizza181 [45]

Answer:

B

Step-by-step explanation:

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galina1969 [7]

Answer:

p = (2k + 1)i + j

q = 25i + (k + 4)j

p . q = 11

Find the dot product of p and q

(2k + 1)(25) + (k + 4) = 11

50k + 25 + k + 4 = 11

51k = -18

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b) p.q = |p||q|cos∅

p= (2k + 1)i + j = [2(-6/17) + 1)i + j ]= 5/17i + j

|p| = √ (5/17)² + 1²

|p| = √314/ 17 ( The square root doesn't cover the 17) = 1.0424

q = 25i + (k + 4)j = 25i + ( -6/17 + 4)j

q = 25i + 62/17 j

|q| = √ 25² + (62/17)²

= 25.2646

Now applying them to the formula above

We already have p.q = 11 from the question.

11 = (1.0424)(25.2646)Cos∅

11 = 26.3358Cos∅

Cos∅ = 11/26.3358

Cos∅ = 0.4177

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This should be it.

Hope it helps

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3 years ago
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