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Tresset [83]
3 years ago
11

Covert 2/3 years to months

Mathematics
2 answers:
natali 33 [55]3 years ago
3 0
Multiply by 12 so 8

thank you hope this helps
sertanlavr [38]3 years ago
3 0

Answer:

7.9 or if you need to round it,it will be 8

Step-by-step explanation:

dont have a explanation nut i hopes this help.

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Can someone plz help me solved this problem plz! I need help ASAP! Plz help me solved this problem
eduard
For question A it’s y= 2/7
For question B it’s y=8/7
7 0
3 years ago
Read 2 more answers
What is the answer for 528÷2
neonofarm [45]
264



Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
5 0
2 years ago
At a certain university, the average attendance at basketball games has been 3125. Due to the dismal showing of the team this ye
Neporo4naja [7]

Answer:

The test statistic needed to evaluate the claim is t = -1.08.

Step-by-step explanation:

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.

At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.

This means that \mu = 3125

Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.

This means that n = 9, X = 2915, s = 585

What is the test statistic needed to evaluate the claim?

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}

t = -1.08

The test statistic needed to evaluate the claim is t = -1.08.

6 0
3 years ago
To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks. How many meters did Sonya swim in tho
Strike441 [17]

Answer:

Distance swam by Sonya in 3 weeks = 19740 m

Step-by-step explanation:

To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks.

Number of days in 1 week = 7

Number of weeks she swam = 3

Total number of days she swam = 3 x 7 = 21 days

Distance swam per day = 0.94 km

Total distance swam = Total number of days she swam x Distance swam per day

Total distance swam = 21 x 0.94 = 19.74 km = 19.74 x 1000 m = 19740 m

Distance swam by Sonya in 3 weeks = 19740 m

7 0
3 years ago
Another submarine descent can be represented as y= -240 x where y is the elevation and x is time in hours. How long will it take
Juli2301 [7.4K]

Answer:e

Step-by-step explanation:

The equation for the submarine is given as y =-240x

Where y is the distance of the descent

x is the time in hours

and -240 is the rate of distance per unit time

To calculate how long it will take this submarine to reach the descent

x = y /-240

8 0
3 years ago
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