The best way to balance an equation is to balance one atom at a time.
You start with two Au atoms on the left, so you know the coefficient of Au on the right has to be 2. So at first we get,
Au2S3 + H2 --> 2Au + H2S
Then, notice you have 3 sulfur atoms on the left, so you need three on the right.
Our equation becomes
Au2S3 + H2 --> 2Au + 3H2S
Lastly, we now have six hydrogen atoms on the right, and only two on the left, so we assign a three to the H2 on the left
Au2S3 + 3H2 --> 2Au + 3H2S Is the balanced final equation.
Answer: (D) environmental chemistry
Explanation:
Answer:
The equilibrium will shift left.
Explanation:
Hope this helps <3
Disagree is the awnser to this question
AlPO4----> Al+3 + PO4-3
Ksp= [Al+3] x [PO4-3]= 9.84 x 10^-21
Ksp= (x) (x)= x^2
X^2= 9.84x10-21
x= 9.92 x 10^-11
The molar solubility is 9.92 x 10^-11
