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Drupady [299]
3 years ago
6

30) Which of these statements are true?

Chemistry
2 answers:
anyanavicka [17]3 years ago
5 0
D because the other answers are partially right, but not all right, therefore it is D, 1 and 4.
Katen [24]3 years ago
4 0
D) 1 and 4
Chromosomes are made up of DNA. DNA strands contain short segments called genes.
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____ is the sharing of electrons .
harkovskaia [24]

Answer:

COVALENT BOND

Explanation:

it is a chemical bond that involves the sharing of electrons.

4 0
3 years ago
He particles are mostly free of each other influence is solid , liquid , gas
Simora [160]

the most free particles are gases, then liquids, solids

4 0
4 years ago
If 1.72 mol of ZnS is heated in the presence of 3.04 mol pf O2,which is the limiting reactant?
gulaghasi [49]

Answer:

The limiting reactant is the ZnS

Explanation:

The equation for this reaction is:

2 ZnS + 3O₂ = 2 ZnO + 2 SO₂

2 moles of zinc sulfure reacts with 3 moles of oxygen.

Then, 1.72 mol of ZnS would react with ( 1.72 .3)/2 = 2.58 moles of O₂

If we have 3.04 moles, then the oxygen is the reactant in excess.

Let's confirm, the ZnS as the limiting reactant.

3 moles of oxygen react with 2 moles of sulfure.

Then, 3.04 moles of O₂ would react with (3.04 .2) / 3 = 2.02 moles of ZnS

We have 1.72 moles of Zn S and it is not enough for the 2.02 moles that we need, for the reaction.

6 0
4 years ago
The specific heat of copper metal is 0.385 J/(g × °C). How much energy must be added to a 35.0 gram sample of copper to change t
Montano1993 [528]
Q = mC∆T 

<span>where: </span>
<span>q = heat </span>
<span>m = mass of substance = 35.0 grams </span>
<span>C = 0.385 J/g*C </span>
<span>∆T = change in temperature = 65C - 20C = 45C </span>

<span>q = (35.0 g)*(0.385 J/g*C)*(45C) = 606 J </span>
3 0
3 years ago
How can you use a barium chloride solution to help identify a sulfate solution?
Igoryamba

answer explanation:

  • <u>Sulfate ions in solution, SO 4 2 -, are detected using barium chloride solution. The test solution is acidified using a few drops of dilute hydrochloric acid, and then a few drops of barium chloride solution are added. A white precipitate of barium sulfate forms if sulfate ions are present.</u>
6 0
2 years ago
Read 2 more answers
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