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liraira [26]
3 years ago
15

Why would a block of wood have more friction than a cube

Chemistry
1 answer:
-BARSIC- [3]3 years ago
6 0
Because the block of wood is more bigger and thicker
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How do ionic bonds form between atoms?
rosijanka [135]
Ionic bonds result from the electrostatic attraction between oppositely charged ions, which form when valence electrons are transferred from one atom to another.
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3 years ago
Why do compounds have different conductivity values if they are the same type of compound?
Karolina [17]
Compounds have different conductivity because if they have the same meaning it wont be a other word. the compounds have to have a conductivity so there can be more meanings.
8 0
4 years ago
Based only on the distance between the valence electron and the nucleus, which atom has a stronger attraction between its nucleu
nirvana33 [79]

Answer:

The atom having less atomic size.

Explanation:

Because the atom having less atomic size means having less atomic number are more close to nucleus so it having more attraction with respect to having large atomic size as it is far from the nucleus.

8 0
3 years ago
A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder
Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

PV_1=nRT

where,

P = pressure of gas = 1 atm

V_1 = volume of gas = ?

T = temperature of gas = 270^oC=273+270=543K

n = number of moles of gas = 0.205 mol

R = gas constant  = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K

V_1=9.12L

Now we have to calculate the volume at 24°C.

PV_2=nRT

where,

P = pressure of gas = 1 atm

V_2 = volume of gas = ?

T = temperature of gas = 24^oC=273+24=297K

n = number of moles of gas = 0.205 mol

R = gas constant  = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K

V_2=4.99L

Now we have to calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 9.12 L

V_2 = final volume = 4.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (4.99-9.12)L

w=4.13L.artm=4.13\times 101.3J=418.4J

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0
3 years ago
Hi can someone hellp this is grade 7
saw5 [17]

Explanation:

option B kinetic energy

hope this helps you!

3 0
2 years ago
Read 2 more answers
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