Answer:
The given functions are


The sine function has a standard period of
by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is
.
Now, the images of each function is the y-variable set values that defines each function.
So, the function
has an image defined by the set
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to
.
About the second function
, the image set is
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
Answer:
40·(1 - 0.15)·0.06 = 2.04
or
36.04·0.06/1.06 = 2.04
Answer:
they did not have enough materials
Step-by-step explanation:
Answer:
-3 7/2
Step-by-step explanation:
the reciperacol of -3 2/7 is just the inverse opposite of that number. i think