Remark
The problem with A and B is that one or the other is always possible. So one of them should be your answer.
Comment
This problem depends on whether or not you believe the two statements are connected in some way.
Does he go to the bank to deposit money, or is that the only time he can go to the bank is on the days that he gets paid?
The problem is not clear enough to make a decision. So your answer is either B or D.
I would say your safest choice is D. You don't know for certain what his motivations are.
D <<<<<<< answer.
Answer:
irrational
Step-by-step explanation:
Answer:
10 makes this equation true
Step-by-step explanation:
2x -4 = 16 /+4
2x= 20 /÷2
x= 10
Test
2(10) - 4 = 16
20 - 4 = 16 Correct
Joe wants to build a fence for his dog Charlie.
The lengths of the perimeter of the rectangle that he plans to surround with fence are as follows:
10 feet + 15 feet + 10 feet + 15 +feet.
The total perimeter area of a rectangle is worked out as follows:
10 + 15 + 10 + 15 = 50
Therefore Joe needs 50 feet of fencing to totally surround the rectangle with fence.
Answer:
- 14π/9; 108°; -√2/2; √2/2
Step-by-step explanation:
To convert from degrees to radians, use the unit multiplier 
In equation form that will look like this:
- 280° × 
Cross canceling out the degrees gives you only radians left, and simplifying the fraction to its simplest form we have 
The second question uses the same unit multiplier, but this time the degrees are in the numerator since we want to cancel out the radians. That equation looks like this:
× 
Simplifying all of that and canceling out the radians gives you 108°.
The third one requires the reference angle of
.
If you use the same method as above, we find that that angle in degrees is 135°. That angle is in QII and has a reference angle of 45 degrees. The Pythagorean triple for a 45-45-90 is (1, 1, √2). But the first "1" there is negative because x is negative in QII. So the cosine of this angle, side adjacent over hypotenuse, is 
which rationalizes to 
The sin of that angle is the side opposite the reference angle, 1, over the hypotenuse of the square root of 2 is, rationalized, 
And you're done!!!