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Kryger [21]
3 years ago
7

Help me no link please ​

Mathematics
2 answers:
ryzh [129]3 years ago
4 0

Answer:

2450

Step-by-step explanation:

You have the size of one of the playgrounds area's, but remember, there are 2. So double your answer.

Genrish500 [490]3 years ago
3 0

Answer:

is it only my or is the picture like static

Step-by-step explanation:

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What is 1,112 rounded to the nearest thousand?
DENIUS [597]

Answer: 1000

because you round down

7 0
3 years ago
X+2y=6 <br> SHOW ALL OF YOUR WORK!
Alika [10]

Answer:

x+2y=6

Subtract 2y from both sides.

x=6−2y

Step-by-step explanation:

x=6-2y

3 0
3 years ago
Read 2 more answers
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
What is 1 6/9 +5 9/7
lisabon 2012 [21]

\longrightarrow{\green{7  \frac{20}{21}}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

1 \frac{6}{9}  + 5  \frac{9}{7}  \\   \\ =  \frac{15}{9}  +  \frac{44}{7}  \\  \\  =  \frac{15 \times 7}{9 \times 7}  +  \frac{44 \times 9}{7 \times 9}  \\  \\  =  \frac{105 + 396}{63}  \\  \\  =   \frac{501}{63}  \\  \\  =  \frac{167}{21}  \\  \\  = 7  \frac{20}{21}

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

6 0
3 years ago
Parameter and Statistic. In a Harris Interactive survey of 2276 adults in the United States, it was found that 33% of those surv
ankoles [38]

Answer:

Our population of interest represent all the adults in United states who never travel using commercial airlines.

The sample on this case represent the people surveyed in United States who never travel using commercial airlines.

For this case the value obtained \hat p =0.33 represent a statistic since is a value who represent the sample not the population. Our population parameter is not known and is given by p

Step-by-step explanation:

A statistic is a "characteristic of a sample". And the statistic allows "estimate the value of a population parameter".

A parameter is a value who represent the population of interest.  

For this case we have a sample size of size n = 2276

The proportion estimated \hat p of people that nevel travel using commercial airlines was:

\hat p = \frac{x}{2276}=0.33 or 33%

Our population of interest represent all the adults in United states who never travel using commercial airlines.

The sample on this case represent the people surveyed in United States who never travel using commercial airlines.

For this case the value obtained \hat p =0.33 represent a statistic since is a value who represent the sample not the population. Our population parameter is not known and is given by p

4 0
3 years ago
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